c++ - 使用 iomanip 时遇到问题，列未按我预期的方式排列

Question

完成一个长项目，最后一步是确保我的数据排列在正确的列中。简单的。只有我在这方面遇到了麻烦，而且我在这方面的时间比我承认观看了很多视频的时间还要长，而且我真的不知道该怎么做所以这是我遇到问题的一小段代码:

 #include <iostream>
 #include <iomanip>   


 using namespace std;

 int main(){        

    cout << "Student Grade Summary\n";
    cout << "---------------------\n\n";
    cout << "BIOLOGY CLASS\n\n";
    cout << "Student                                   Final   Final Letter\n";
    cout << "Name                                      Exam    Avg   Grade\n";
    cout << "----------------------------------------------------------------\n";
    cout << "bill"<< " " << "joeyyyyyyy" << right << setw(23) 
         << "89" << "      " << "21.00" << "   "
         << "43" << "\n";
    cout << "Bob James" << right << setw(23)  
         << "89" << "      " << "21.00" << "   "
         << "43" << "\n";
    }

这适用于第一个条目，但 bob james 条目的数字全都歪了。我以为 setw 应该让你忽略它？我错过了什么？谢谢

Answer 1

并不是你想的那样。 std::setw 仅为下一次插入设置字段宽度(即 it is not "sticky" )。

尝试这样的事情:

#include <iostream>
#include <iomanip>

using namespace std;

int main() {

    cout << "Student Grade Summary\n";
    cout << "---------------------\n\n";
    cout << "BIOLOGY CLASS\n\n";

    cout << left << setw(42) << "Student" // left is a sticky manipulator 
         << setw(8) << "Final" << setw(6) << "Final"
         << "Letter" << "\n";
    cout << setw(42) << "Name"
         << setw(8) << "Exam" << setw(6) << "Avg"
         << "Grade" << "\n";
    cout << setw(62) << setfill('-') << "";
    cout << setfill(' ') << "\n";
    cout << setw(42) << "bill joeyyyyyyy"
         << setw(8) << "89" << setw(6) << "21.00"
         << "43" << "\n";
    cout << setw(42) << "Bob James"
         << setw(8) << "89" << setw(6) << "21.00"
         << "43" << "\n";
}

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