c++ - 将两个相关类的数据写入文件

Question

我在将一些数据写入文件时遇到问题。

#include <iostream>
#include <iomanip>
#include <string>
#include <fstream>

using namespace std;

class Person{
public:
    Person();
    Person(string, string);
    string getFirst();
    string getLast();
private:
    string firstName, lastName;
};

class Employee{ 
public:
    Employee::Employee();
    Employee(string, string, float);
    Person getName();
    float getPay();
private:
    Person hiredHand;
    float salary;
};

Person::Person()
    :firstName(""), lastName("")
{
}

Person::Person(string first, string last)
    : firstName(first), lastName(last)
{
}

string Person::getFirst()
{
    return firstName;
}

string Person::getLast()
{
    return lastName;
}

Employee::Employee()
    : hiredHand("", ""), salary(0)
{
}

Employee::Employee(string first, string last, float sal)
    : hiredHand(first, last), salary(sal)
{
}

Person Employee::getName()
{
    return hiredHand;
}

float Employee::getPay()
{
    return salary;
}

int main()
{
    string first, last;
    float salary;

    cout << "Enter a first name, last name, and a salary." << endl;
    cin >> first >> last >> salary;
    Employee person1(first, last, salary);

    ofstream fileOut("Output.txt");
    if (!fileOut)
    {
        cerr << "Unable to open file for reading." << endl;
        exit(1);
    }

    Person guy1 = person1.getName();

    fileOut << guy1.getFirst << endl;
    fileOut << guy1.getLast << endl;
    fileOut << fixed << setprecision(2) << "$" << person1.getPay() << endl;
    fileOut.close();
}

我不确定如何从 Employee 类中提取 Person 类中的数据。我的目标是能够在文件的不同行中打印出名字、姓氏和薪水。到目前为止只有工资有效..

更新:

我已经向 Person 类添加了一些 setter/getter ，但是当我尝试打印它时它给了我一个错误。

Error1: error C3867: 'Person::getFirst': function call missing argument list; use '&Person::getFirst' to create a pointer to member 
Error2: error C3867: 'Person::getLast': function call missing argument list; use '&Person::getLast' to create a pointer to member   

Answer 1

你指的是这个吗？

string Person::getFirstName()
{
  return firstName;
}

然后:

string Employee::getFirstName()
{
    return hiredHand.getFirstName();
}

或者，您可以改为尝试此解决方案(如果我们坚持您的示例):

fileOut << guy1.getFirst() << endl;
fileOut << guy1.getLast() << endl;