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c++ - _BLOCK_TYPE_IS_VALID(pHead->nBlockUse) 在 "return 0"之后

转载 作者:行者123 更新时间:2023-11-30 01:49:05 27 4
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我正在编写一个程序,我必须在其中编写自己的字符串类和药水类。我知道这个运行时错误通常是在程序删除未分配的内容时引起的,但它发生在 main 中的“return 0”之后。我已经逐行调试它并尝试了一些方法来尝试消除运行时错误,但没有任何效果。有没有人可以帮我解决这个问题?

这是我的代码:

//Main
#include "Potion.h"
#include <iostream>
using std::cout;
using std::endl;

void TotalCost( Potion ArrayofPotions[5] )
{
String Currency[4] = {"Platinum", "Gold", "Silver" ,"Copper"};
int TotalCost[4] = {0, 0, 0, 0};
int Cost[4] = {0, 0, 0, 0};

for (short i = 0; i < 5; i++)
{
for (short k = 0; k < 4; k++)
{
Cost[k] = ArrayofPotions[i].ConvertCost(k);
TotalCost[k] += Cost[k];

if ( i != 0 )
TotalCost[k] = ArrayofPotions[k].CalculateCost(TotalCost[k - 1], TotalCost[k]);
}
}
cout << "\nTotal cost for all potions: ";

for (short i = 0; i < 4; i++)
{
cout << TotalCost[i] << ' ';
Currency[i].Display();
}
}

int main()
{
Potion Haggling("Potion of Haggling", "You haggle for 10% better prices for 30 seconds",
"Weak", "0.80.0.4.");

Potion Strength("Draught of Strength", "You can carry 20% more for 300 seconds",
"Low", "2.60.5.1.");

Potion Health("Solution of Health", "You are 30% tougher for 60 seconds",
"Mild", "2.20.5.1.");

Potion Stealth("Philter of Stealth", "You are 40% harder to detect for 60 seconds",
"Moderate", "0.90.5.1.");

Potion Waterbreathing("Elixir of Waterbreathing", "You can breathe underwater for 60 seconds",
"Strong", "2.10.5.0.");

Potion ArrayOfPotions[5] = {Haggling, Strength, Health, Stealth, Waterbreathing};

for (short i = 0; i < 5; i++)
ArrayOfPotions[i].DisplayPotions();

TotalCost(ArrayOfPotions);

system("pause");
return 0;
}

//String class
class String
{
public:
String() : m_str(nullptr)
{ }
String(char chr) : m_str(nullptr)
{
m_str = new char;
*m_str = ch;
}
String(char * str)
{
if (str != nullptr)
{
m_str = new char[strlen(str) + 1];
strcpy(m_str, str);
}
}
String(const String & copy) : m_str(copy.m_str)
{ }
String& operator=(const String & rhs)
{
if ( this != &rhs )
{
delete [] m_str;
m_str = new char[strlen(rhs.m_str) + 1];
strcpy(m_str, rhs.m_str);
}

return *this;
}
~String()
{
delete [] m_str;
}
void Display() const
{
cout << m_str;
}
char * GetStr() const
{
return m_str;
}
String Upper()
{
char * check = this->m_str;

for (unsigned short i = 0; i < strlen( this->m_str ); i++, check++)
{
if ( *check > 96 && *check < 123 )
{
*check -= 32;
}
else
m_str = this->m_str;
}
return m_str;
}
private:
char * m_str;
};

//Potion class

#include "String.h"

class Potion
{
public:
Potion() : m_name(nullptr), m_description(nullptr), m_potency(nullptr),
m_cost(nullptr)
{ }
Potion(String name, String description, String potency, String cost)
{
m_name = name;
m_description = description;
m_potency = potency.Upper();
m_cost = cost;
}
Potion(const Potion & copy) : m_name(copy.m_name), m_description(copy.m_description),
m_potency(copy.m_potency), m_cost(copy.m_cost)
{ }
int ConvertCost(int index)
{
int cost = 0;
char * new_cost = m_cost.GetStr();
char * temp_string = new char[strlen( new_cost ) + 1];

strcpy(temp_string, new_cost);

char * temp = strtok( temp_string, "." );

for (short k = 0; k != index; k++)
temp = strtok( NULL, "." );

cost = atoi( temp );

delete [] temp_string;

return cost;
}
int CalculateCost(int & cost1, int cost2)
{
if (cost > 99)
{
cost1++;
cost2 -= 100;
}
return cost2;
}
void DisplayPotions()
{
String Currency[4] = {"Platinum", "Gold", "Silver" ,"Copper"};
int cost = 0;

m_name.Display();
m_description.Display();
m_potency.Display();

for (short i = 0; i < 4; i++)
{
cost = ConvertCost(i);

if (cost != 0)
{
cout << ConvertCost(i) << ' ';
Currency[i].Display();
}
}
}
private:
String m_name;
String m_description;
String m_potency;
String m_cost;
};

很抱歉,它真的很长,我遗漏了一些输出格式,但我真的需要一些帮助。

附言我的教授希望我们将成本从字符串转换为 int,并且必须将其放入“0.0.0.0”格式。这就是为什么它是这样写的。

最佳答案

您的赋值运算符已损坏,因为它从右侧复制了指针。
您需要遵循与复制构造函数中相同的过程。

顺便说一句,复制构造函数也被破坏了,因为如果 rhs 为空,它将失败。

(在空字符串的表示中使用空字符串是一个更安全的想法(即使用 "" 而不是 nullptr)。
它使您免于进行大量空检查。)

这个构造函数也坏了:

String(char * str)
{
if (str != nullptr)
{
m_str = new char[strlen(str) + 1];
strcpy(m_str, str);
}
}

因为如果您将 m_str 传递给 nullptr ,它会保留未初始化的状态 - 您会经常这样做。

这个构造函数也坏了:

String(char chr) : m_str(nullptr)
{
m_str = new char;
*m_str = ch;
}

因为它不构造以零结尾的字符串。

你需要

m_str = new char[2];
m_str[0] = ch;
m_str[1] = 0;

关于c++ - _BLOCK_TYPE_IS_VALID(pHead->nBlockUse) 在 "return 0"之后,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29601870/

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