java - 将xml字符串转换为java对象: getting `details` as null?

Question

我一直在尝试将 xml 字符串转换为 Java 对象。

有一个 TV 的根标签。其中有多个字段，但我希望整个内容作为一个字符串。

@XmlRootElement(name = "TV")
@XmlAccessorType(XmlAccessType.FIELD)
public class TV {
    @XmlElement
    public String details;
    public String getDetails() {
        return details;
    }
    public void setDetails(String details) {
        this.details = details;
    }
    @Override
    public String toString() {
        return "TV [details=" + details + "]";
    }   
}


public class XMLtoJavaObject {

    public static void main(String[] args) {
        String xmlString = "<TV version=\"0.91fn\"><channel><title>Friends</title><link>https://www.imdb.com/title/tt0108778/</link><season>2</season></channel></TV>";
        JAXBContext jaxbContext;
        try {
            jaxbContext = JAXBContext.newInstance(TV.class);
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            TV tv = (TV) jaxbUnmarshaller.unmarshal(new StringReader(xmlString));
            System.out.println("TV" + tv);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}

输出:

TV [details=null]

我没有将整个嵌套 xml 作为字符串。

有人可以帮我解决我所缺少的吗？

提前致谢

Answer 1

试试这个:

电视类别:

@XmlRootElement(name = "TV")
@XmlAccessorType(XmlAccessType.FIELD)
public class TV {

    @XmlElement
    private Channel channel;

    public Channel getChannel() {
      return channel;
    }

    public void setChannel(Channel channel) {
      this.channel = channel;
    }

    @Override
    public String toString() {
      return "TV [channel=" + channel + "]";
    }
}

channel 类:

@XmlAccessorType(XmlAccessType.FIELD)
public class Channel {
  @XmlElement
  private String title;
  private String link;
  private String season;

  public String getTitle() {
    return title;
  }

  public void setTitle(String title) {
    this.title = title;
  }

  public String getLink() {
    return link;
  }

  public void setLink(String link) {
    this.link = link;
  }

  public String getSeason() {
    return season;
  }

  public void setSeason(String season) {
    this.season = season;
  }

  @Override
  public String toString() {
    return "Channel [title=" + title + ", link=" + link + ", season=" + season + "]";
  }

}

输出:

TVTV [channel=Channel [title=Friends, link=https://www.imdb.com/title/tt0108778/, season=2]]

现在您可以根据需要使用 Java 获取您的详细信息，例如:

tv.getChannel().getTitle();