java - 使用 Jackson 将单个 java 字段映射到两个 JSON 字段

Question

POJO中有一个isCase字段，它同时映射到case和is_case(这不是预期的)。删除 @JsonProperty 注释会删除 json 中的 is_case 字段，但 is_case 是它应该的样子。将 @JsonIgnore 放在 isCase 上并不会消除响应 json 中的大小写。将 isCase 重命名为 is_case 确实消除了响应 json 中的大小写，但这似乎不太正确。为什么 Jackson 会将单个 java 字段映射到两个字段？POJO 声明如下:

public class CreateRuleResponse {
    @JsonProperty(value = "rule_name", required = true)
    private String name;

    @JsonProperty("rule_num")
    private String ruleNum;

    @JsonProperty(value = "rule_category")
    private RuleCategory ruleCategory;

    @JsonProperty(value = "rule_status")
    private RuleStatus ruleStatus;

    @JsonProperty(value = "rule_channel_type")
    private String ruleChannelType;

    @JsonProperty("action")
    private RuleAction ruleAction;

    @JsonProperty("is_case")
    private Boolean isCase;

    public CreateRuleResponse() {
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getRuleNum() {
        return ruleNum;
    }

    public void setRuleNum(String ruleNum) {
        this.ruleNum = ruleNum;
    }

    public RuleCategory getRuleCategory() {
        return ruleCategory;
    }

    public void setRuleCategory(RuleCategory ruleCategory) {
        this.ruleCategory = ruleCategory;
    }

    public RuleStatus getRuleStatus() {
        return ruleStatus;
    }

    public void setRuleStatus(RuleStatus ruleStatus) {
        this.ruleStatus = ruleStatus;
    }

    public String getRuleChannelType() {
        return ruleChannelType;
    }

    public void setRuleChannelType(String ruleChannelType) {
        this.ruleChannelType = ruleChannelType;
    }

    public RuleAction getRuleAction() {
        return ruleAction;
    }

    public void setRuleAction(RuleAction ruleAction) {
        this.ruleAction = ruleAction;
    }

    public Boolean getCase() {
        return isCase;
    }

    public void setCase(Boolean aCase) {
        isCase = aCase;
    }
}

Answer 1

它映射变量以及 getter 方法。