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java - 用随机列表中的 2 个值填充 2D 数组(2048 游戏)

转载 作者:行者123 更新时间:2023-11-30 01:43:15 26 4
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我正在尝试重新创建 2048 游戏,但遇到了困难并被难住了。我已经用二维数组制作了网格,它似乎工作正常。然后,我制定了一种方法来存储此网格/数组中的空/可用空间列表,以便可以将两个起始数字分配给两个随机的可用空间。我的问题是我无法让数字显示在实际网格内。我的代码如下,如果有人能告诉我哪里出错了,我将不胜感激。如果我解释得很糟糕,我很抱歉,我对 Java 还很陌生。

import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;

public class Main {
//Game Board Size Method - Getting User Number to use for dimension of game board
public static int gameBoardSize() {
int number = 0;
int row = 0;
Scanner in = new Scanner(System.in);
System.out.println("Welcome to 1024");
System.out.print("Please select a number between 4 & 8 to determine the size of your game board: "); //Prompt user to select number
number = in.nextInt(); //Storing number in variable
if (number >= 4 && number <= 8) { //If number is >= 4 and <= 8
row = number; //Assign number to row variable
} else {
System.out.print("Error, please select a number between 4 & 8"); //Error print message
}
return row; //Return
}

//Display Game board method - Array for game board grid and to display the grid.
public static void displayGameBoard(int[][] gameBoard, int gameBoardSize) {
String divider;
switch (gameBoardSize) {
case 5:
divider = "\n+-----+-----+-----+-----+-----+"; //User Number 5
break;
case 6:
divider = "\n+-----+-----+-----+-----+-----+-----+"; //User Number 6
break;
case 7:
divider = "\n+-----+-----+-----+-----+-----+-----+-----+"; //User Number 7
break;
case 8:
divider = "\n+-----+-----+-----+-----+-----+-----+-----+-----+"; //User Number 8
break;
default:
divider = "\n+----+-----+-----+----+"; //User Number 4
}
System.out.println(divider); //Printing Divider at top
for (int i = 0; i < gameBoard.length; i++) {
for (int j = 0; j < gameBoard[i].length; j++) {
if (gameBoard[i][j] == 0) { //If both i & j is == 0
System.out.print("| "); //Print this left border
}
if (j == gameBoard[j].length - 1) { //If 2nd array length -1 (end)
System.out.print("|"); //Print end border
}
}

System.out.println(divider); //Printing Divider at bottom
}
}



public static int[][] createGameBoard(int userRows) {
return new int[userRows][userRows]; //Returning rows
}


//Method to loop through array to find empty space
public static int[][] findEmptyCells(int[][] gameBoard) {
int freeCellCount = 0;
int[][] emptyList = new int[gameBoard.length * gameBoard.length][2];
for (int i = 0; i < gameBoard.length; i++) {
for (int j = 0; j < gameBoard[i].length; j++) {
if (gameBoard[i][j] == 0) {
emptyList[freeCellCount][0] = i;
emptyList[freeCellCount][1] = j;
freeCellCount++;
}
Random rnd = new Random();
int rndPair = rnd.nextInt(freeCellCount);
emptyList[rndPair][0] = i;
emptyList[rndPair][1] = j;
}
}
return emptyList;
}

//Use WASD: W for up, S for Down, A for Left and D for Right
public static void instructions() {
System.out.println("How to Play");
System.out.println("Press W to move up");
System.out.println("Press S to move down");
System.out.println("Press A to move left");
System.out.println("Press D to move right");
}



public static void main(String[] args) {
int rows = gameBoardSize();
int[][] gameBoard = createGameBoard(rows);
displayGameBoard(gameBoard, rows);
instructions();
int[][] findEmptyCells = findEmptyCells(gameBoard);
}
}

最佳答案

除非您要求使用打印到控制台来创建此游戏 - 我会尽快放弃此方法。在一个设计不像动画 Pane 的空间中创建像 2048 这样的游戏将非常困难且令人沮丧。

相反,我会让每个图 block 都是一个对象,并对 Java 中的 swing 和 Graphics 进行一些研究。

如果你必须这样做,(顺便说一下,检查你设置网格的方式 - 它的间距不一致)你必须打印“|”之间的值字符。

什么是明智的方法?那么,您可以创建一个 2D int 数组 int[][],并将所有值存储在游戏板上。然后,您可以循环遍历二维数组中的每个元素,并将其打印在“|”之间人物。 下面的示例适用于任何大小的二维数组。尝试更改传入的值的数量并注意其行为

public class Test {
private static int[][] temp = new int[][] {{0,2, 4},{4, 4,16}, {3, 0, 128}};

public static void main(String[] args) {
int rows = temp.length;
int cols = temp[0].length;

for (int i = 0; i < rows; i++) {
// This will resize our row separator for each row
for (int j = 0; j < cols; j++) {
System.out.print("+-----");
}

System.out.print("+\n");

for (int j = 0; j < cols; j++) {
System.out.print("|");

// Here you have to deal with the spacing. You can see that this is ugly.
// There's definitely better ways to do this, such as using mod
if (temp[i][j] == 0) {System.out.print(" ");}
else if (temp[i][j] < 10) {System.out.print(" " + temp[i][j] + " ");}
else if (temp[i][j] < 100) {System.out.print(" " + temp[i][j] + " ");}
else if (temp[i][j] < 1000) {System.out.print(" " + temp[i][j] + " ");}
}

System.out.print("|\n");
}

for (int j = 0; j < cols; j++) {
System.out.print("+-----");
}

System.out.print("+\n");
}
}

上面程序的输出:

+-----+-----+-----+
| | 2 | 4 |
+-----+-----+-----+
| 4 | 4 | 16 |
+-----+-----+-----+
| 3 | | 128 |
+-----+-----+-----+

但是,还有保持间距正确的问题。您需要考虑数字的长度,因为如果数字为空白,则必须打印正确数量的空格。或者你必须使用replace()...这听起来很困惑。

关于java - 用随机列表中的 2 个值填充 2D 数组(2048 游戏),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59200967/

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