java - 如何使用Java在Android中生成每个项目具有不同背景颜色的微调器？

Question

我想用Java生成一个用于颜色选择的微调器，下拉时它应该看起来像这样:

我的 Java 代码现在如下所示:

    final Spinner spinner = new Spinner(context);
    String[] colors = new String[]{"[1]", "[2]", "[3]", "[4]", "[5]", "[6]"};
    final List<String> colorsList = new ArrayList<>(Arrays.asList(colors));
    final ArrayAdapter<String> spinnerArrayAdapter = new ArrayAdapter<String>(context, android.R.layout.simple_spinner_item, colorsList) {
      @Override
      public View getDropDownView(int position, View convertView, ViewGroup parent) {
        View view = super.getDropDownView(position, convertView, parent);
        TextView tv = (TextView) super.getDropDownView(position, convertView, parent);
        Color color = Color.rgb(18,18,218);
        switch(position){
           case 0:
              color = Color.rgb(28,158,218); 
              break;
           case 1:
              color = Color.rgb(218,58,218); 
              break;
           case 2:
              color = Color.rgb(128,18,28); 
              break;
        }
        return view;
      }
    };

但是现在没有显示任何颜色，全是白色。更好的方法是什么？

Answer 1

将 BackgroundColor 设置为 view，而不是 TextView。 除此之外如果您想对所选 View 进行着色，那么您还必须重写getView。检查以下内容:

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    return getCustomView(position, convertView, parent);
}

@Override
public View getDropDownView(int position, View convertView, ViewGroup parent) {
    return getCustomView(position, convertView, parent);
}

private View getCustomView(int position, View convertView, ViewGroup parent) {
    View view = super.getDropDownView(position, convertView, parent);

    if (position % 2 == 1) {
        view.setBackgroundColor(Color.parseColor("#FFC3C0AA"));
    }
    else {
        view.setBackgroundColor(Color.parseColor("#FFB5DCE8"));
    }

    return view;
}

输出: