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php - JQGrid,如何将 JSON 字符串发送到 PHP 进行处理并发送到数据库?

转载 作者:行者123 更新时间:2023-11-30 01:38:11 24 4
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好的,我有多个选定的行,我想将它们发送到数据库 onclick。创建选定数据行的字符串,firebug 显示它们发布的内容。但是我无法将其发布到 php 并作为新条目发送到数据库。请帮助。此外,我想在发送到不同的表后从数据库中删除行。请给我生死攸关的帮助。

jqgrid[编辑]终于将其发布到数据库中了。唯一的问题是每个选择都会发布 7 次。我希望它为每个选择只发布一个。有什么帮助吗?

$(function(){ 
$("#list").jqGrid({
url:'request.php',
editurl: "sendyo.php",
datatype: 'xml',
mtype: 'GET',
multiselect:true,
multiboxonly:true,
height: 450,
width: 850,

colNames:['id','Project', 'Assigned To','Assign Date','Check Date','Due Date','Attachments'],
colModel :[
{name:'id', index:'id', width:25},
{name:'name', index:'name', width:250, align:'left',editable:true, editoptions:{
size:60} },
{name:'id_continent', index:'id_continent', width:55, align:'right',editable:true,edittype:'select',
editoptions:{value: "Henry:Henry; Ramon:Ramon; Paul:Paul" },mtype:'POST' },

{name:'lastvisit', index:'lastvisit', width:70, align:'right',formatter: 'date',srcformat:'yyyy-mm-dd',newformat: 'm-d-Y',editable:true, edittype: 'text',mtype:'POST' ,editoptions:{size:10, dataInit:function(elem){$(elem).datepicker({dateFormat:'m/d/yy'});}}} ,


{name:'cdate', index:'cdate', width:70, align:'right',formatter: 'date',srcformat:'yyyy-mm-dd',newformat: 'm-d-Y', edittype: 'text',editable:true ,mtype:'POST' ,editoptions:{size:10, dataInit:function(elem){$(elem).datepicker({dateFormat:'m/d/yy'});}}} ,

{name:'ddate', index:'ddate', width:70, align:'right',formatter: 'date',srcformat:'yyyy-mm-dd',newformat: 'm-d-Y',date:'true',editable:true, edittype: 'text',editoptions:{size:10, dataInit:function(elem){$(elem).datepicker({dateFormat:'m/d/yy'});}}} ,


{name:'email', index:'email', width:70,align:'center',sortable:false,mtype:'POST' }
],
pager: '#pager',
rowNum:20,
rowList:[20,40,80],
sortname: 'id',
sortorder: 'desc',
viewrecords: true,
gridview: true,
caption: 'Pending Assignments',

ondblClickRow: function(rowid) {

$(this).jqGrid('editGridRow', rowid,
{width:450,Height:400,recreateForm:true,closeAfterEdit:true,
closeOnEscape:true,reloadAfterSubmit:false, modal:true,mtype:'post'});}


});


jQuery("#minibutton").click( function(){

var selectedrows = $("#list").jqGrid('getGridParam','selarrrow');
if(selectedrows.length) {
for(var i=0;i<selectedrows.length; i++) {

var selecteddatais = $("#list").jqGrid('getRowData',selectedrows[i]);
var rows=JSON.stringify(selecteddatais)
var postArray = {json:rows};

$.ajax({
type: "POST",
url: "jsonsend.php",
data: postArray,
dataType: "json",
error: function () {
alert("An error occurred.");
},
success: function (data) {
}
});
$( '#list' ).trigger( 'reloadGrid', [{ page: 1}] );//reload grid}
}}


});
});

PHP:

   // connect to the MySQL database server
$con = mysql_connect($dbhost, $dbuser, $dbpassword);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
@mysql_select_db($database,$con) or die("Error connecting to db.");




//First decode the array
$arr = $_POST["json"];
$decarr = json_decode($arr, true);

$count = count($decarr);

$values = array(); // This will hold our array values so we do one single insert

for ($x=0; $x < $count; $x++){
$newrec = $decarr;
$id = $newrec['id']; $id = mysql_real_escape_string($id);
$name = $newrec['name']; $name = mysql_real_escape_string($name);
$id_continent = $newrec['id_continent']; $id_continent = mysql_real_escape_string($id_continent);
$email = $newrec['email']; $email = mysql_real_escape_string($email);
$lastvisit = $newrec['lastvisit']; $lastvisit = mysql_real_escape_string($lastvisit);
$cdate = $newrec['cdate']; $cdate = mysql_real_escape_string($cdate);
$ddate = $newrec['ddate']; $ddate = mysql_real_escape_string($ddate);


// Create insert array
$values[] = "('".$id."', '".$name."', '".$id_continent."', '".$lastvisit."','".$cdate."','".$ddate."','".$email."' )";



}

// Insert the records

$sql = "INSERT INTO finish (id, name, id_continent, lastvisit,cdate,ddate, email)
VALUES ".implode(',', $values);

$result = mysql_query($sql, $con) or die(mysql_error());


?>

最佳答案

简单地删除了多余的帖子定义。

//First decode the array
$arr = $_POST["json"];
$decarr = json_decode($arr, true);
$count = count($decarr);


for ($x=0; $x < $count; $x++){
$newrec = $decarr;
$id = $newrec['id'];
$name = $newrec['name'];
$id_continent = $newrec['id_continent'];
$email = $newrec['email'];
$lastvisit = $newrec['lastvisit'];
$cdate = $newrec['cdate'];
$ddate = $newrec['ddate'];

}

// Create insert array
$values[] = "('".$id."', '".$name."', '".$id_continent."', '".$lastvisit."','".$cdate."','".$ddate."','".$email."' )";





// Insert the records

$sql = "INSERT INTO finish (id, name, id_continent, lastvisit,cdate,ddate, email)
VALUES ".implode(',', $values);

$result = mysql_query($sql, $con) or die(mysql_error());


?>

关于php - JQGrid,如何将 JSON 字符串发送到 PHP 进行处理并发送到数据库?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16553066/

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