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c++ - 具有可变参数类型的模板多重可变继承

转载 作者:行者123 更新时间:2023-11-30 01:35:44 24 4
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我需要多次继承以下类,将可变参数作为模板参数。

template <class SignalDispatcherClass, class ... ArgTypes>
class ISignalMap
{
//private
public:

void RegisterSlot(SignalAddress pSignalFunc, ISlotInvoker<ArgTypes...>* pSlotInvoker)
{
//implementation
}
};

到目前为止,我可以扩展参数包并获得多个类特化,但函数只接受一个参数。

template <class SignalDispatcherClass, class ... ArgTypes>
class ISignalStorage : public ISignalMap<SignalDispatcherClass, ArgTypes>...
{
};

///////
ISignalStorage<SignalA, int, double, bool> iss;

目前,这允许我使用单个参数(相应的 int、double 或 bool)注册槽函数。我需要的是看起来像这样的东西:

ISignalStorage<SignalA, <int, double, bool>, <int, int>, <const char*>> iss;

到目前为止,我一直在研究其他问题,其中一个似乎与主题有些接近,但我未能实现或理解它。希望有更简单的方法(Variadic variadic template templates)

添加:代码示例

struct IDummySlot
{
void FuncDbl(double)
{}
void FuncInt(int)
{}
void FuncIntDbl(int, double)
{}
};

template <class ... Args>
struct ISlotInvoker
{};

template <class SignalDispatcherClass, class ... ArgTypes>
class ISignalMap
{
public:

void RegisterSlot(void(IDummySlot::*pSignalFunc)(ArgTypes...), ISlotInvoker<ArgTypes...>* pSlotInvoker)
{
return;
}
};

template <class SignalDispatcherClass, class ... ArgTypes>
class ISignalStorage : public ISignalMap<SignalDispatcherClass, ArgTypes>...
{
};


int main()
{
ISignalStorage<IDummySlot, int, double> iss;

ISlotInvoker<int> slot_int;
ISlotInvoker<double> slot_double;
ISlotInvoker<int, double> slot_intDouble;

//iss.RegisterSlot(&IDummySlot::FuncInt, &slot_int); //ambigous
/*Appears to be that I didn't test it, I just saw that inheritance worked as I expected, but didn't try to invoke*/

return 0;
}

enter image description here

最佳答案

这里的根本问题是没有从单个参数包中“压缩”多个可变参数包的语法。

在这种情况下,通常的做法是使用 std::tuple 来包装每个单独的参数包,并从这些元组中创建一个参数包:

    ISignalStorage<foo, std::tuple<int, double>, std::tuple<double, int>> a;

然后,使用特化从 std::tuple 中解包每个参数包就变成了一件简单的事情:

#include <tuple>


template <class SignalDispatcherClass, class ... ArgTypes>
class ISignalMap
{
};

// Take a class, and a tuple. Give me an ISignalMap for the class, and
// what's in the tuple.

template<typename cl, typename tuple_t> struct tuple_expansion;

template<typename cl, typename ...tuple_types>
struct tuple_expansion<cl, std::tuple<tuple_types...>> {

typedef ISignalMap<cl, tuple_types...> type;
};

// Syntactic sugar.
template<typename cl, typename tuple_t>
using tuple_expansion_t=typename tuple_expansion<cl, tuple_t>::type;

// And a variadic parameter pack of tuples...

template <class SignalDispatcherClass, class ... ArgTypes>
class ISignalStorage : public tuple_expansion_t<SignalDispatcherClass,
ArgTypes>...
{
};

class foo;

void bar()
{

// Note the syntax: pass each "inner" parameter pack wrapped into a
// tuple.
ISignalStorage<foo, std::tuple<int, double>, std::tuple<double, int>> a;

ISignalMap<foo, int, double> &b=a;
ISignalMap<foo, double, int> &c=a;
}

关于c++ - 具有可变参数类型的模板多重可变继承,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53434669/

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