c++ - 如何从键盘读取 C++ 中可变数量的整数？

Question

我需要从键盘读取可变数量的整数，以便我可以使用它们中的每一个。

首先我想我可以使用类似的东西

    int myinteger;
    for (int i=0; i<MAX_NUMBER_OF_INTEGERS; i++){
    cin >> myinteger;
    //What I want to do with that Integer
    }

但后来我意识到如果 MAX_NUMBERS_OF_INTEGERS = 10 我必须写 10 个整数。但我想要的是我可以传递“1 2 3”“1 2 3 4”(例如)而不必写 10 个整数。

Answer 1

这个问题自从被问到并给出了一个很好的答案后，似乎发生了一些变化。这只是为了回答新问题。

#include <iostream>
#include <sstream>
#include <vector>

const int MAX_NUMBERS_OF_INTEGERS = 10;

int main() {
    std::string line;
    std::cout << "Enter at most " << MAX_NUMBERS_OF_INTEGERS << " ints, separated by spaces: ";
    std::getline(std::cin, line);

    // create a string stream of the line you entered
    std::stringstream ss(line);

    // create a container for storing the ints
    std::vector<int> myInts;

    // a temporary to extract ints from the string stream
    int myInteger;

    // extract at most MAX_NUMBERS_OF_INTEGERS ints from the string stream
    // and store them in the container
    while(myInts.size()<MAX_NUMBERS_OF_INTEGERS && ss>>myInteger) myInts.push_back(myInteger);

    std::cout << "Extracted " << myInts.size() << " integer(s)\n";

    // loop through the container and print all extracted ints.
    for(int i : myInts) {
        std::cout << i << "\n";
    }
    // ... or access a certain int by index
    if(myInts.size() > 2)
        std::cout << "The third int was: " << myInts[2] << "\n";

}