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mysql - 通过映射表选择值。

转载 作者:行者123 更新时间:2023-11-30 01:35:00 25 4
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我有三个表senderTablerecieverTable和一个ma​​pTable。我正在尝试编写一个查询来获取 senderNamerecieverName 的输出

发件人表

senderID
senderName

接收表

recieverID
recieverName

map 表

mappingID
senderID
recieverID

我有以下查询,该查询不起作用,因为我不知道如何将映射表合并到其中。

SELECT t_senderTable.nameFull AS "senderName", t_recieverTable.recieverName AS "recieverName" 
FROM ((dbo.t_senderTable AS t_senderTable
INNER JOIN t_senderTable AS t_senderTable ON (t_senderTable.Kd = mapTable.senderID))
INNER JOIN t_recieverTable AS t_recieverTabler ON (recieverTable.Id = mapTable.recieverID ))

有什么想法可以正确执行吗?谢谢

最佳答案

这是您要找的吗?

SELECT t_senderTable.nameFull AS "senderName"
, t_recieverTable.recieverName AS "recieverName"
FROM dbo.t_senderTable AS t_senderTable
INNER JOIN mapTable
ON t_senderTable.Id = mapTable.senderID
INNER JOIN t_recieverTable AS t_recieverTabler
ON mapTable.recieverID = recieverTable.Id

关于mysql - 通过映射表选择值。,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17030887/

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