C++迭代字符串中空格不规则的单词

Question

假设我们有一个字符串，单词之间的空格不规则，如下所示:

roberto           1007   2.3  6.4  7127016 534260   ??  S    10:18AM   5:32.46 /Applications/Firefox.app/Contents/MacOS/firefox  

如何创建一个包含所有单词的数组？

这是我的基本解决方案:

std:: string = "roberto           1007   2.3  6.4  7127016 534260   ??  S    10:18AM   5:32.46 /Applications/Firefox.app/Contents/MacOS/firefox  ";   
size_t length = strlen(string.data());
std::vector<std::string> words;
std::string temp;
for (int i = 0; i < length; i++) {
    if (string[i] != ' ') {
        temp.push_back(string[i]);
    } else {
        if (!temp.empty()) {
            words.push_back(temp);
            temp = "";
        }
    }
}

std::cout << "words are: " << std::endl;
for (const auto &word : words) {
    std::cout << word << std::endl;
}

感谢您的关注。

Answer 1

流操作删除前导空格。

#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <sstream>

template<typename T>
std::ostream& operator<<(std::ostream& os, const std::vector<T>& vec)
{
    for (auto& el : vec)
    {
        os << el << std::endl;
    }
    return os;
}

int main()
{
    std::string input = "roberto           1007   2.3  6.4  7127016 534260   ??  S    10:18AM   5:32.46 /Applications/Firefox.app/Contents/MacOS/firefox  ";
    std::istringstream iss(input);
    std::vector<std::string> results(std::istream_iterator<std::string>{iss}, {});

    std::cout << results << std::endl;
}

See it live