c++ - 在 C++ 中将电话号码中的字母转换为数字

Question

我整天都在盯着这个看，这段代码让我感到很困难。我需要这个程序来将一串字母(例如 Call Cash)转换为 7 位数的电话号码。我得到两种结果之一。该程序要么根本不输出任何数字，要么陷入无限循环。如有任何帮助，我们将不胜感激。

// Program to convert letters to numbers in a phone number.

//Header file
#include <iostream>
#include <iomanip>

using namespace std;

int main ()
{
    //Declare variables
char input;
char letters;
int number;
int counter;
counter = 0;


    //Program
cout << "Enter Y/y to convert a telephone number form letters to digits." << endl;
cout << "Enter any other letter to terminate the program." << endl;
cin >> input;
while (input == 'Y' || input == 'y')
{
    cout << "Enter telephone number using letters: ";
    cin >> letters;
    cout << endl;

    cout << "The corresponding phone number is: ";

    while (counter <= 7);
    {
        cout << number;
        if ((letters >= 'A' && letters <= 'Z') || (letters >= 'a' && letters <= 'z'))
        switch (letters)
    {
    case 'A':
    case 'a':
    case 'B':
    case 'b':
    case 'C':
    case 'c':
    cout << "2";
    break;

    case 'D':
    case 'd':
    case 'E':
    case 'e':
    case 'F':
    case 'f':
    cout << "3";
    break;

    case 'G':
    case 'g':
    case 'H':
    case 'h':
    case 'I':
    case 'i':
    cout << "4";
    break;

    case 'J':
    case 'j':
    case 'K':
    case 'k':
    case 'L':
    case 'l':
    cout << "5";
    break;

    case 'M':
    case 'm':
    case 'N':
    case 'n':
    case 'O':
    case 'o':
    cout << "6";
    break;

    case 'P':
    case 'p':
    case 'Q':
    case 'q':
    case 'R':
    case 'r':
    case 'S':
    case 's':
    cout << "7";
    break;

    case 'T':
    case 't':
    case 'U':
    case 'u':
    case 'V':
    case 'v':
    cout << "8";
    break;

    case 'W':
    case 'w':
    case 'X':
    case 'x':
    case 'Y':
    case 'y':
    case 'Z':
    case 'z':
    cout << "9";
    break;

    if (counter == 3)
        cout << "-";
}
    }
}


return 0;
}

编辑:这是我的新代码。我现在遇到的问题是它只返回第一个字母的值，并且在单独的行上返回每个值。我非常感谢您的帮助:

    //Declare variables
char input;
char letters;
int number;
int i;


    //Program
cout << "Enter Y/y to convert a telephone number form letters to digits." << endl;
cout << "Enter any other letter to terminate the program." << endl;
cin >> input;
while (input == 'Y' || input == 'y')
{
    cout << "Enter telephone number using letters: ";
    cin >> letters;
    cout << endl;

    cout << "The corresponding phone number is: ";

    for(int i = 0; i < 7; i++)
    {
        if ((letters >= 'A' && letters <= 'Z') || (letters >= 'a' && letters <= 'z'))
        switch (letters)
    {
    case 'A':
    case 'a':
    case 'B':
    case 'b':
    case 'C':
    case 'c':
    cout << "2";
    break;

    case 'D':
    case 'd':
    case 'E':
    case 'e':
    case 'F':
    case 'f':
    cout << "3";
    break;

    case 'G':
    case 'g':
    case 'H':
    case 'h':
    case 'I':
    case 'i':
    cout << "4";
    break;

    case 'J':
    case 'j':
    case 'K':
    case 'k':
    case 'L':
    case 'l':
    cout << "5";
    break;

    case 'M':
    case 'm':
    case 'N':
    case 'n':
    case 'O':
    case 'o':
    cout << "6";
    break;

    case 'P':
    case 'p':
    case 'Q':
    case 'q':
    case 'R':
    case 'r':
    case 'S':
    case 's':
    cout << "7";
    break;

    case 'T':
    case 't':
    case 'U':
    case 'u':
    case 'V':
    case 'v':
    cout << "8";
    break;

    case 'W':
    case 'w':
    case 'X':
    case 'x':
    case 'Y':
    case 'y':
    case 'Z':
    case 'z':
    cout << "9";
    break;
    cout << number;
    }

    if (i == 2)
        cout << "-";

    }
    cout << "To process another telephone number, enter Y/y." << endl;
    cout << "Enter any other letter to terminate the program." << endl;
    cin >> input;
}


return 0;

Answer 1

你的 while (counter <= 7) 后面有一个分号.您放错了 switch (letters) 的右括号，它应该在 if (counter == 3) 之前 .你有一个 while循环 input ，但您永远不会在程序运行时更改它。

我都得到了吗？