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android - 如何通过单个查询从内容提供者中检索所有联系人详细信息?

转载 作者:行者123 更新时间:2023-11-30 01:29:35 25 4
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我需要从设备读取联系人。我需要的字段是 ID , Display Name, Phone Number (All types) Email id (All types)和“照片”。为此,我现在正在这样做。

1 :首先,我从 ContactsContract.Contacts.CONTENT_URI; 中读取所有 id,如下所示

        Uri contactsUri = ContactsContract.Contacts.CONTENT_URI;
// Querying the table ContactsContract.Contacts to retrieve all the contacts
String[] projection = {ID};
Cursor contactsCursor = mContentResolver.query(contactsUri, projection, null, null,
"upper(" + ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + ") ASC");

2 : 然后遍历此游标以读取所有联系人的必填字段。

if (contactsCursor.moveToFirst()) {
do {
long contactId = contactsCursor.getLong(contactsCursor.getColumnIndex(ID));
Uri dataUri = ContactsContract.Data.CONTENT_URI;
// Querying the table ContactsContract.Data to retrieve individual items like
// home phone, mobile phone, work email etc corresponding to each contact
String[] columns = {CONTACT_ID, PHOTO_URI, DISPLAY_NAME, MIME_TYPE, DATA_1, DATA_2, DATA_4};
String selection = ContactsContract.Data.CONTACT_ID + "=" + contactId;
Cursor dataCursor = mContentResolver.query(dataUri, columns,
selection,
null, null);
if (dataCursor.moveToFirst()) {
// Getting Display Name
displayName = dataCursor.getString(dataCursor.getColumnIndex(ContactsContract.Data.DISPLAY_NAME));
do {
// Getting Phone numbers
String mimeType = dataCursor.getString(dataCursor.getColumnIndex(MIME_TYPE));
switch (mimeType) {
case ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE:
String phoneNumber = dataCursor.getString(dataCursor.getColumnIndex(DATA_1));
switch (dataCursor.getInt(dataCursor.getColumnIndex(DATA_2))) {
case ContactsContract.CommonDataKinds.Phone.TYPE_HOME:
homePhone = phoneNumber;
break;
case ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE:
mobilePhone = phoneNumber;
break;
case ContactsContract.CommonDataKinds.Phone.TYPE_WORK:
workPhone = phoneNumber;
break;
default:
otherPhone = phoneNumber;
}
break;
// Getting emails
case ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE:
switch (dataCursor.getInt(dataCursor.getColumnIndex(DATA_2))) {
case ContactsContract.CommonDataKinds.Email.TYPE_HOME:
homeEmail = dataCursor.getString(dataCursor.getColumnIndex(DATA_1));
break;
case ContactsContract.CommonDataKinds.Email.TYPE_WORK:
workEmail = dataCursor.getString(dataCursor.getColumnIndex(DATA_1));
break;
default:
otherEmail = dataCursor.getString(dataCursor.getColumnIndex(DATA_1));
}
break;
// getting photo Uri
case ContactsContract.CommonDataKinds.Photo.CONTENT_ITEM_TYPE:
if (dataCursor.getString(dataCursor.getColumnIndex(PHOTO_URI)) != null) {
photoUri = Uri.parse(dataCursor.getString(dataCursor.getColumnIndex(PHOTO_URI)));
}
break;
}

} while (dataCursor.moveToNext());


} while (contactsCursor.moveToNext());

查询工作正常,但问题是迭代和获取每个联系人的详细信息需要花费太多时间。第一个查询很快返回,但整个延迟现在在第二部分,即遍历第一个查询的每一行并查询每个字段。这可以在单个连接查询中完成,以便我可以优化性能吗?

最佳答案

是的,您可以在单个查询中执行此操作 - 所有关于联系人的数据实际上都存储在一个表 Data 中,其中包含您需要的有关联系人的所有信息,包括 CONTACT_ID 和 DISPLAY_NAME,它们也是托管在 Contacts 表上。

因此,您基本上需要在单个查询中查询数据表中的所有内容,并使用 HashMap 从 CONTACT_ID 到某个联系人对象(或者如果您更喜欢详细信息列表)将其分类为联系人).

(注意:确保仅从 ContactsContract 包中导入以下类)

Map<Long, List<String>> contacts = new HashMap<Long, List<String>>();

String[] projection = {Data.CONTACT_ID, Data.DISPLAY_NAME, Data.MIMETYPE, Data.DATA1, Data.DATA2, Data.DATA3, Data.PHOTO_ID};
String selection = Data.MIMETYPE + " IN ('" + Phone.CONTENT_ITEM_TYPE + "', '" + Email.CONTENT_ITEM_TYPE + "')";
Cursor cur = cr.query(Data.CONTENT_URI, projection, selection, null, null);

while (cur != null && cur.moveToNext()) {
long id = cur.getLong(0);
String name = cur.getString(1);
String mime = cur.getString(2); // email / phone / company
String data = cur.getString(3); // the actual info, e.g. +1-212-555-1234
int type = cur.getInt(4); // a numeric value representing type: e.g. home / office / personal
String label = cur.getString(5); // a custom label in case type is "TYPE_CUSTOM"
long photoId = cur.getLong(6);

String kind = "unknown";
String labelStr = "";

switch (mime) {
case Phone.CONTENT_ITEM_TYPE:
kind = "phone";
labelStr = Phone.getTypeLabel(getResources(), type, label);
break;
case Email.CONTENT_ITEM_TYPE:
kind = "email";
labelStr = Email.getTypeLabel(getResources(), type, label);
break;
}
Log.d(TAG, "got " + id + ", " + name + ", " + kind + " - " + data + " (" + labelStr + ")");

// add info to existing list if this contact-id was already found, or create a new list in case it's new
List<String> infos;
if (contacts.containsKey(id)) {
infos = contacts.get(id);
} else {
infos = new ArrayList<String>();
infos.add("name = " + name);
infos.add("photo = " + photoId);
contacts.put(id, infos);
}
infos.add(kind + " = " + data + " (" + labelStr + ")");
}

关于android - 如何通过单个查询从内容提供者中检索所有联系人详细信息?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35959508/

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