c++ - 将 C++ 代码从 VS2003 迁移到 VS2010 后出现错误 C2678，错误 C2679 : binary '=' : no operator found which takes a right-hand operand of type 'int'

Question

std::vector<std::string>::iterator it;

it = NULL;
do
{
    if(it == NULL)
        it = init.begin();
    else
        ++it;
    if(it == init.end())
        return 1; 
}
while(it->empty());

上面这段代码在VS2003上运行良好，但是当它迁移到VS2010时，它给出编译错误说

error C2679: binary '=' : no operator found which takes a right-hand operand of type 'int' (or there is no acceptable conversion)
1>          c:\program files\microsoft visual studio 10.0\vc\include\vector(388): could be 'std::_Vector_iterator<_Myvec> &std::_Vector_iterator<_Myvec>::operator =(const std::_Vector_iterator<_Myvec> &)'
1>          with
1>          [
1>              _Myvec=std::_Vector_val<std::string,std::allocator<std::string>>
1>          ]
1>          while trying to match the argument list '(std::_Vector_iterator<_Myvec>, int)'
1>          with
1>          [
1>              _Myvec=std::_Vector_val<std::string,std::allocator<std::string>>
1>          ]
1>d:\vs2010_ws\acct ford 6.2.4 source code\acct_ford_ws\vector\src\driver\cancardxl.cpp(81): error C2678: binary '==' : no operator found which takes a left-hand operand of type 'std::_Vector_iterator<_Myvec>' (or there is no acceptable conversion)
1>          with
1>          [
1>              _Myvec=std::_Vector_val<std::string,std::allocator<std::string>>
1>          ]

Answer 1

您假设可以从 int(或某种形式的指针？)初始化和分配 vector 迭代器。事实并非如此。

您可以将循环转换为类似以下内容:

if (init.empty())
  return 1;

it = init.begin();
while (it->empty())
{
  ++it;
  if (it == init.end())
    return 1;
}