gpt4 book ai didi

c++ - 如何分析、查找和修复 C++ 函数中的安全漏洞?

转载 作者:行者123 更新时间:2023-11-30 01:24:26 24 4
gpt4 key购买 nike

<分区>

作为工作示例,我们可以处理以下代码:

    #include <sys/socket.h>

#define size_t SOCKET

int receive_socket_data(SOCKET sock,//socket representing remote connection
unsigned long& version_number,//validPtr->version #
unsigned long& message_size,//validPtr->sizeof packet
char*& buf // where to copy data from packet
)
{
int nlen = 0;
buf = NULL;

// Receive version_number from the packet
nlen = recv(sock, (char*) &version_number, sizeof(version_number), 0);
if (nlen == 0 || nlen == -1) return ERROR_RECEIVING;
version_number = ntohl(version_number);

// Receive message_size from the entire packet
// (ulong + ulong + sizeof data)
nlen = recv(sock, (char*) &message_size, sizeof(message_size), 0);
if (nlen == 0 || nlen == -1) return ERROR_RECEIVING;
message_size = ntohl(message_size);
// Allocate a buffer to copy the data part of the packet
buf = new char[message_size + 1 - 2 * sizeof(unsigned long)];
buf[message_size - 2 * sizeof(unsigned long)] = '\0';

// Copy the data part from the packet to the buffer
if (recv(sock, (char*) buf, message_size-2*sizeof(unsigned long), 0) == -1)
return ERROR_RECEIVING;

return SUCCESS_RECEIVING;
}

例如,我想到的是运算符 new 可能抛出的错误。
我不确定数组的索引计算是否也会导致问题。

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com