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mysql - SQLzoo 教程 | GROUP BY 和 HAVING

转载 作者:行者123 更新时间:2023-11-30 01:23:57 27 4
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我无法正确回答以下问题

Show the years in which three prizes were given for Physics.

我编写了以下脚本,但它返回错误。

SELECT yr, COUNT(subject) FROM nobel
WHERE subject = 'Physics'
GROUP BY yr
HAVING COUNT(subject) = 3

感谢您的宝贵时间

最佳答案

该查询看起来正确,但如果没有指向 SqlZoo 页面的链接,我无法确定。

尝试

SELECT yr FROM nobel
WHERE subject = 'Physics'
GROUP BY yr
HAVING COUNT(subject) = 3

——您返回的结果的确切格式可能很挑剔。它只要求年份。

关于mysql - SQLzoo 教程 | GROUP BY 和 HAVING,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18218315/

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