gpt4 book ai didi

php - 使用 mysql 连接 android 和 php 时发生错误

转载 作者:行者123 更新时间:2023-11-30 01:22:12 25 4
gpt4 key购买 nike

我的 post_item.java 文件中有以下代码:

package com.iwantnew.www;

import java.util.ArrayList;
import java.util.List;

import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.app.ProgressDialog;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class post_item extends Activity {
private ProgressDialog pDialog;
JSONParser jsonParser = new JSONParser();
Button add_room;
EditText contact_no;
EditText no_of_room;
EditText price_per_room;
EditText description;

private static String url_create_product = "http://10.0.2.2/android_iwant/android_add_room.php";

private static final String TAG_SUCCESS = "success";

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.post_form);

//contact_no = (EditText) findViewById(R.id.contact_no);
no_of_room = (EditText) findViewById(R.id.no_of_room);
price_per_room = (EditText) findViewById(R.id.price_per_room);
//description = (EditText) findViewById(R.id.description);
contact_no = (EditText) findViewById(R.id.contact_no);

add_room = (Button) findViewById(R.id.add_room);

add_room.setOnClickListener(new View.OnClickListener() {

@Override
public void onClick(View v) {
// creating new product in background thread
new add_new_room().execute();
}
});
}
// suru...
class add_new_room extends AsyncTask<String, String, String> {

/**
* Before starting background thread Show Progress Dialog
* */
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(post_item.this);
pDialog.setMessage("Saving details..");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}

/**
* Creating product
* */
protected String doInBackground(String... args) {
//String contact = contact_no.getText().toString();
String quantity = no_of_room.getText().toString();
String price = price_per_room.getText().toString();
//String contact = contact_no.getText().toString();
String descriptions = description.getText().toString();

// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
//params.add(new BasicNameValuePair("contact", contact));
params.add(new BasicNameValuePair("quantity", quantity));
params.add(new BasicNameValuePair("price", price));
params.add(new BasicNameValuePair("descriptions", descriptions));

// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_create_product,
"POST", params);

// check log cat fro response

Log.d("Create Response", json.toString());

// check for success tag
try {
int success = json.getInt(TAG_SUCCESS);

if (success == 1) {
// successfully created product
Intent i = new Intent(getApplicationContext(), MainActivity.class);
startActivity(i);

// closing this screen
finish();
} else {
// failed to create product
}
} catch (JSONException e) {
e.printStackTrace();
}

return null;
}

/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once done
pDialog.dismiss();
}

}
}

而且,我的 php 文件中有以下内容:

<?php

/*
* Following code will create a new product row
* All product details are read from HTTP Post Request
*/

// array for JSON response
$response = array();

// check for required fields

if (isset($_POST['quantity']) && isset($_POST['price'])) {

//$location = $_POST['location'];
$quantity = $_POST['quantity'];
$price = $_POST['price'];
//$productID = $_POST['area'];
//$contact = $_POST['contact'];
$descriptions = $_POST['descriptions'];

// include db connect class
require_once __DIR__ . '/db_connect.php';

// connecting to db
$db = new DB_CONNECT();

// mysql inserting a new row
$result = mysql_query("INSERT INTO room_tb(uid,categoryID,quantity,price,description) VALUES(5,1,'$quantity','$price','$descriptions')");
//$result1 = mysql_query("INSERT INTO users(userContactNumber) VALUES('$contact')");

// check if row inserted or not
if($result)/*&& ($result1)*/ {
// successfully inserted into database
$response["success"] = 1;
$response["message"] = "Room added successfully.";

// echoing JSON response
echo json_encode($response);
} else {
// failed to insert row
$response["success"] = 0;
$response["message"] = "Oops! An error occurred.";

// echoing JSON response
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";

// echoing JSON response
echo json_encode($response);
}
?>

每当我将描述或联系电话发送到数据库时,Android模拟器都会说“意外停止工作”,并且没有记录进入数据库。但是,如果我只传递 quantitypricecategoryIDuid,则不会发生错误并记录转到数据库。我做错了什么?

这是我的日志猫 http://pastebin.com/WvBPs2gs 的链接

最佳答案

Caused by: java.lang.NullPointerException
07-15 02:06:36.366: E/AndroidRuntime(2918): at com.iwantnew.www.post_item$add_new_room.doInBackground(post_item.java:96)

因此,无论第 96 行有什么内容,它都是空的,应该进行检查。您的代码 fragment 中没有行号,但我认为这与描述变量的使用有关:

String descriptions = description.getText().toString();

而变量描述的赋值在注释中设置

//description = (EditText) findViewById(R.id.description);

关于php - 使用 mysql 连接 android 和 php 时发生错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18414561/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com