php - 我如何检查特定 mysql 表的特定列的任何行中是否存在值

Question

我需要使用脚本检查数据库中是否存在值。该值基于变量，字段是 LONGTEXT。

// ...:::BEGIN REGISTRATION:::...

//Add key format for hikashop
$pay = "PayPal transaction id: $pay";

$link = mysql_connect($host, $user, $pass);
mysql_select_db($dbo);
if (!$link)
  {
  die('Could not connect');
  }

// check if Transaction ID is available on the default website.
$query = mysql_query ("SELECT * FROM jh23m_hikashop_history WHERE history_data = '$pay'");
$result = mysql_num_rows($query);
echo $result;

// Verifica che esiste almeno una riga contente la transazione. 
// Se si procedi con la response e salva nel db, altrimenti rispondi che la key non è stata trovata.
if ($result == 0){
    die ('Your transaction has not been found. Please enter your payment transaction correctly or contact the support');
}

奇怪的是，有些值被发现了，但很多却没有!$pay 来自 $_POST，我添加了 $pay = "PayPal transaction id: $pay";使其格式化为商店网站的格式。

请帮忙!

编辑:我编写了一部分代码，尝试看看为什么这不匹配。这是通过 ARRAY 得到的结果:数组 ( [0] => [1] => 0JW61238FU6854240 [2] => 5EA00979GC149044V [3] => 59P88560S9783170B [4] => 1L697134B06956638 [5] => 1N476458GR470922M [6] => 3N4412142S083993R [7] => 2GN69713EV7294613 [ 8] => 9WT48148YE725931K [9] => 585690586Y6998523 [10] => 7X9149767T051513K [11] => 5WJ25963L5455313H [12] => 1L717841BA5989748 [13] => 0E750230DV1575308 [14] => 85B43558SH819711N [15] => 78R85507FR2081540 [16] => 96F7363575285431M [17] => 87V99180GV2251342 [18] => 4G459145SE959020V [19] => 86U00726DL9205244 [20] => 70820350T9653825F [21] => 8 K002091YN0079914 [22] => 8SD993824R7167708 [23] => 93L886231K973983G [24] => 6E98077468505954G [25] => 770172708D596892K [26] => 22N679682U615734D [27] => 3WR4000656945550Y [28] => 59P88560S9783170B [29] => 8H 242117S01162917 [30] => 9WC47475K89394047 [31] => 83L6687699339330K [32] => 1BE09674W4880373N [ 33] => 3JC01978GH9146509 [34] => 31381161BJ159335S [35] => 17V97629HJ1941344 [36] => 4XG15144CK988864F [37] => 18625833YF123353H [38] => 2GU86013NN2703635 ) 不 matco0JW61238FU6854240

我尝试了这种脚本来看看为什么:

// check if Transaction ID is available on the default website.
$query = mysql_query ("SELECT * FROM jh23m_hikashop_history");
$result = mysql_num_rows($query);
while(($row = mysql_fetch_array($query))) {
    $paypal_ids[] =$row['history_data'];
}
//print_r ($paypal_ids);
// ora cerca il valore %pay
$paypal_ids_split = implode("", $paypal_ids);
//print_r ($paypal_ids_split);
$paypal_ids_clean = explode ("PayPal transaction id: ", $paypal_ids_split);
print_r ($paypal_ids_clean);

if (in_array($pay, $paypal_ids_clean)){
    echo "Match";
} else 
{ echo "Does not matco";
}
echo $pay;

还是不匹配？搞什么？

但是如果我使用它，它会匹配!!搞什么？匹配:59P88560S9783170B

是否有可能某些字节使其变脏？

Answer 1

我从不久前发现的有关此问题的帖子中保存了此内容。

while ($row = mysql_fetch_array($result, MYSQL_ASSOC))

然后您可以使用 MYSQL_NUM 切换回数字，或者使用 MYSQL_BOTH 切换回数字