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c++ - 为什么 strtok 不能与 stringstream 一起使用?

转载 作者:行者123 更新时间:2023-11-30 01:19:30 25 4
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考虑这些参数:

char words[8] = "one two";
string word1;
string word2;
stringstream ss;

这段代码的输出:

ss << strtok(words, " ");
ss >> word1;
ss << strtok(NULL, " ");
ss >> word2;
cout << "Words: " << word1 << " " << word2 << endl;

是:

Words: one

这段代码

ss << strtok(words, " ");
ss >> word1;
char* temp = strtok(NULL, " ");
word2 = temp;
cout << "Words: " << word1 << " " << word2 << endl;

输出是:

Words: one two

为什么stringstream可以处理strtok的第一个返回值,但不能处理第二个?

最佳答案

你应该插入语句

ss.clear();

清除流的eof状态。例如

    char words[8] = "one two";
std::string word1;
std::string word2;
std::stringstream ss;
ss << std::strtok(words, " ");
ss >> word1;
ss.clear();
ss << std::strtok(NULL, " ");
ss >> word2;
std::cout << "Words: " << word1 << " " << word2 << std::endl;

关于c++ - 为什么 strtok 不能与 stringstream 一起使用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20814378/

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