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php - 如何在条形图mysql中回显carno的名称

转载 作者:行者123 更新时间:2023-11-30 01:15:01 26 4
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如何在 barhcart 车辆编号中回显车辆名称

我该怎么做,请帮我解决这个问题

谢谢

现在是这样显示的 enter image description here

我想要这样

enter image description here

我该怎么做,请帮助我

这是 mysql 表

---------------------------------------------
id | carno | name | amount
---------------------------------------------
1 | 1066D | abcd | 26.641
2 | 1126mr | ana | 32.764
3 | 1145hw | adil | 47.876
4 | 1176ml | xyz | 188.46
5 | 1452ys | demmo3 | 84.875
6 | 1467by | name | 52.819
7 | 1504yd | bali | 101.732
---------------------------------------------

这里是 barchart.php

<?php
include 'config.php';
$link=mysql_connect("$hostname","$username","$password")or
die('Could not connect: ' . mysql_error());
mysql_select_db("$dbname",$link);
include 'create.php';
$sql="SELECT carno, sum(amount) AS amount FROM $tablename GROUP BY carno"; // Give Your field Name
$result = mysql_query($sql);
$graphtitle='BarChart';//Graph Title
$xname='Year'; //X-axis Name
$yname='Values';//y-axis name
$img_width=400;//image height
$img_height=300;//image width
$margins=70;
$ymargin=6;
$count=mysql_affected_rows();
$graph_width=$img_width - $margins * 2;
$graph_height=$img_height - $margins * 2;
$bar_width=25;
$total_bars=$count;
$gap= ($graph_width- $total_bars * $bar_width ) / ($total_bars +1);
$img=imagecreate($img_width,$img_height);
include 'barcolor.php';
imagefilledrectangle($img,0,0,0,0,$bag_color);
imageline($img,$margins,$img_height-45,$img_width-20,$img_height-45,$xyline_color);
imageline($img,$margins,$ymargin,$margins,$img_height-45,$xyline_color);
$maxvalue="select max(date) as amount from $tablename";//Give your field name for Y axis
$max=mysql_query($maxvalue);
while($inf1= mysql_fetch_array($max))
{
$ratio=$graph_height/$inf1[0];
}
$horizontal_lines=8;
$horizontal_gap=($img_height+20)/$horizontal_lines;
for($j=1;$j<=$horizontal_lines;$j++)
{
$y=($img_height-48) - $horizontal_gap * $j ;
//imageline($img,$margins+1,$y,$img_width-20,$y,$hline_color);
$v=intval($horizontal_gap * $j /$ratio);
imagestring($img,2,$margins-30,$y-5,$v,$values_color);
}
$i=0;
while($inf = mysql_fetch_array($result))
{
$x1=($margins+10) + ($gap+5) + $i * ($gap+$bar_width) ;
$x2=$x1+$bar_width;
$y1=($img_height-46)- ceil($inf[1] * $ratio) ;
$y2=($img_height-46);
imagestring($img,2,$x1+1,$y1-15,$inf[1],$values_color);
imagestring($img,2,$x2-23,$img_height-43,$inf[0],$values_color);
imagefilledrectangle($img,$x1,$y1,$x2,$y2,$bar_color); // Draw bar
$i++;
}
imagestring($img,8, ($img_width-$margin)/2, 0, $graphtitle, $txt_color);
imagestring($img,5, ($img_width-$margin)/2, $img_height-($ymargin+10), $xname, $txt_color);
imagestringup($img,5,10,($img_height-$ymargin)/2, $yname, $txt_color);
//header('Content-type: image/png');
imagepng($img, 'barchart.jpg');
echo "<div style='border:1px solid #d8d8d8;width:$img_width'><img src='barchart.jpg'></div>";
?>

这里是 barcolor.php

<?php
$bag_color=imagecolorallocate($img,246,246,246);//Baground color
$xyline_color=imagecolorallocate($img,135,135,135);//XY-axis color
$bar_color=imagecolorallocate($img,172,212,123);//Bar color
$values_color=imagecolorallocate($img,2,2,2);//values color
$txt_color=imagecolorallocate($img,227,113,39);//text color
?>

这里是config.php

<?php

$username = "root";
$password = "";
$hostname = "localhost";
$dbname = "car";
$tablename = "fuel";

?>

最佳答案

只需将 SQL 更改为

$sql="SELECT CONCAT(carno,' ','(',name,')') as name, sum(amount) AS amount FROM $tablename GROUP BY carno";

关于php - 如何在条形图mysql中回显carno的名称,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19151337/

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