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android - 实现 Google Play 游戏服务 - 如何让用户登录

转载 作者:行者123 更新时间:2023-11-30 01:05:01 26 4
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这是我第一次使用 google API,因为我对 android 编程还很陌生。我一直在尝试在我的应用程序中实现 google play 游戏服务和显示排行榜(您可能已经猜到这是一款游戏),但在遵循 google 文档时遇到了一些困难。

我设置了一个按钮,想让用户在点击它时登录,并让用户保持登录状态,直到他们之后注销。我已经按照文档对此进行了编程:

public class MainActivity extends AppCompatActivity implements View.OnClickListener, GoogleApiClient.ConnectionCallbacks, GoogleApiClient.OnConnectionFailedListener {

Button bLeaderboard;

private GoogleApiClient mGoogleApiClient;

private static int RC_SIGN_IN = 9001;

private boolean mResolvingConnectionFailure = false;
private boolean mAutoStartSignInflow = true;
private boolean mSignInClicked = false;


@Override
@SuppressLint("NewApi")
protected void onCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

bLeaderboard = (Button) findViewById(R.id.bLeaderboard);
bLeaderboard.setOnClickListener(this);

mGoogleApiClient = new GoogleApiClient.Builder(this)
.addConnectionCallbacks(this)
.addOnConnectionFailedListener(this)
.addApi(Games.API).addScope(Games.SCOPE_GAMES)
.build();
}

@Override
public void onClick(View v) {
switch (v.getId()) {

case R.id.bLeaderboard:

mSignInClicked = true;
mGoogleApiClient.connect();
}

}

问题是,每当我点击排行榜按钮时,应用程序就会崩溃,并且会收到此错误消息:

AndroidRuntime: FATAL EXCEPTION: main Process: com.example.game, PID: 26284 java.lang.IllegalStateException: A fatal developer error has occurred. Check the logs for further information. at com.google.android.gms.common.internal.zzd$zza.zzc(Unknown Source) at com.google.android.gms.common.internal.zzd$zza.zzv(Unknown Source) at com.google.android.gms.common.internal.zzd$zze.zzasf(Unknown Source) at com.google.android.gms.common.internal.zzd$zzd.handleMessage(Unknown Source) at android.os.Handler.dispatchMessage(Handler.java:102) at android.os.Looper.loop(Looper.java:148) at android.app.ActivityThread.main(ActivityThread.java:5417) at java.lang.reflect.Method.invoke(Native Method) at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726) at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)

我也一直无法理解如何处理这三个已实现的方法:

@Override
public void onConnected(@Nullable Bundle bundle) {
}

@Override
public void onConnectionSuspended(int i) {
}

@Override
public void onConnectionFailed(@NonNull ConnectionResult connectionResult) {

}

非常感谢任何帮助,因为除了谷歌的文档之外我找不到任何关于这方面的教程,正如我之前所说,我很难理解和遵循它。

最佳答案

这对我来说是正确的

 public class MainActivity extends ActionBarActivity implements  GoogleApiClient.ConnectionCallbacks, GoogleApiClient.OnConnectionFailedListener {

// Client used to interact with Google APIs
private GoogleApiClient mGoogleApiClient;
private static int RC_SIGN_IN = 9001;

private boolean mResolvingConnectionFailure = false;
private boolean mAutoStartSignInflow = true;
private boolean mSignInClicked = false;
GameHelper gameHelper;



@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);


mGoogleApiClient = new GoogleApiClient.Builder(this)
.addConnectionCallbacks(this)
.addOnConnectionFailedListener(this)
.addApi(Games.API).addScope(Games.SCOPE_GAMES)
.build();
gameHelper = new GameHelper(this, GameHelper.CLIENT_GAMES);
gameHelper.enableDebugLog(true);
gameHelper.setup(new GameHelper.GameHelperListener() {
@Override
public void onSignInFailed() {
Toast.makeText(getApplicationContext(),"Please Check Your Internet Connection!",Toast.LENGTH_LONG).show();
}

@Override
public void onSignInSucceeded() {
Toast.makeText(getApplicationContext(),"Signed in Succeed",Toast.LENGTH_LONG).show();
}
});



setContentView(view);

//for load all Score card



scorecard=(Button)findViewById(R.id.score_card);
scorecard.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {


startActivityForResult(Games.Leaderboards.getAllLeaderboardsIntent(mGoogleApiClient), 1);

}
});





}
private boolean isScoreResultValid(final Leaderboards.LoadPlayerScoreResult scoreResult) {
return scoreResult != null && GamesStatusCodes.STATUS_OK == scoreResult.getStatus().getStatusCode() && scoreResult.getScore() != null;
}



@Override
protected void onStart() {
super.onStart();
mGoogleApiClient.connect();
}

@Override
protected void onStop() {
super.onStop();
mGoogleApiClient.disconnect();
}

@Override
public void onConnected(Bundle connectionHint) {
// The player is signed in. Hide the sign-in button and allow the
// player to proceed.
// now submit your high_score
Games.Leaderboards.submitScore(mGoogleApiClient,getResources().getString(R.string.leaderboard_easy),high_score);

}

@Override
public void onConnectionFailed(ConnectionResult connectionResult) {
if (mResolvingConnectionFailure) {
// already resolving
return;
}

// if the sign-in button was clicked or if auto sign-in is enabled,
// launch the sign-in flow
if (mSignInClicked || mAutoStartSignInflow) {
mAutoStartSignInflow = false;
mSignInClicked = false;
mResolvingConnectionFailure = true;

// Attempt to resolve the connection failure using BaseGameUtils.
// The R.string.signin_other_error value should reference a generic
// error string in your strings.xml file, such as "There was
// an issue with sign-in, please try again later."
/*if (!BaseGameUtils.resolveConnectionFailure(this,
mGoogleApiClient, connectionResult,
RC_SIGN_IN, "Sign in error")) {
mResolvingConnectionFailure = false;
}*/
}

// Put code here to display the sign-in button
}

@Override
public void onConnectionSuspended(int i) {
// Attempt to reconnect
mGoogleApiClient.connect();
}



protected void onActivityResult(int requestCode, int resultCode,
Intent intent) {
if (requestCode == RC_SIGN_IN) {
mSignInClicked = false;
mResolvingConnectionFailure = false;
if (resultCode == RESULT_OK) {
mGoogleApiClient.connect();
} else {
// Bring up an error dialog to alert the user that sign-in
// failed. The R.string.signin_failure should reference an error
// string in your strings.xml file that tells the user they
// could not be signed in, such as "Unable to sign in."
BaseGameUtils.showActivityResultError(this,
requestCode, resultCode, R.string.signin_failure);
}
}
}
// Call when the sign-in button is clicked
private void signInClicked() {
mSignInClicked = true;
mGoogleApiClient.connect();
}

// Call when the sign-out button is clicked
private void signOutclicked() {
mSignInClicked = false;
Games.signOut(mGoogleApiClient);
}

}

关于android - 实现 Google Play 游戏服务 - 如何让用户登录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38939681/

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