java.io.FileNotFoundException 即使 imageView 可以显示图片

Question

我试图让用户选择的图片通过 POST 请求转到我的网络服务器。所以我需要在 Base64 中对我的图片进行编码，但我遇到了一个问题，logcat 返回了一个我不理解的 FileNotFoundException :

Unable to decode stream: java.io.FileNotFoundException

这是我的 onActivityResult :

 protected void onActivityResult(int requestCode, int resultCode, Intent data) {

    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == RESULT_LOAD_IMAGE && resultCode == RESULT_OK && null != data) {

        final Uri selectedImage = data.getData();
        String[] filePathColumn = {MediaStore.Images.Media.DATA};
        Log.d("Toast", filePathColumn[1]);
        Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
        cursor.moveToFirst();
        int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
        String picturePath = cursor.getString(columnIndex);
        cursor.close();
        imgViewScan.setImageURI(selectedImage);
        try
        {
            InputStream stream = getContentResolver().openInputStream(
                    data.getData());
            Bitmap bm = BitmapFactory.decodeStream(stream);
            BitmapFactory.Options options = new BitmapFactory.Options();
            options.inPreferredConfig = Bitmap.Config.ARGB_8888;
            //Bitmap bm = BitmapFactory.decodeFile(selectedImage.toString(),options);
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            bm.compress(Bitmap.CompressFormat.JPEG, 100, baos); //bm is the bitmap object
            byte[] b = baos.toByteArray();
            String encodedImage = Base64.encodeToString(b, Base64.DEFAULT);
            new EnvoiPhotoTask().execute(encodedImage);
        } catch(IOException e)
        {
            Log.e("ScanAc", e.toString());
        }


    }
}

这是我的 list :

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.partenaires.legimetrie.legimetrieapp">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
<application
    android:allowBackup="true"
    android:icon="@mipmap/ic_launcher"
    android:label="@string/app_name"
    android:supportsRtl="true"
    android:theme="@style/Theme.AppCompat.Light.NoActionBar">
    <activity android:name=".MainActivity">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <activity android:name=".InscriptionActivity" />
    <activity android:name=".ConnexionActivity" />
    <activity android:name=".ServicesActivity" />
    <activity android:name=".InterventionRapideActivity" />
    <activity android:name=".InterventionDetailleeActivity" />
    <activity android:name=".ScanActivity" />
    <activity android:name=".ContactActivity"></activity>
</application>

我有一个函数`

    public static void verifyStoragePermissions(Activity activity) {
    // Check if we have write permission
    int permission = ActivityCompat.checkSelfPermission(activity, Manifest.permission.WRITE_EXTERNAL_STORAGE);

    if (permission != PackageManager.PERMISSION_GRANTED) {
        // We don't have permission so prompt the user
        ActivityCompat.requestPermissions(
                activity,
                PERMISSIONS_STORAGE,
                REQUEST_EXTERNAL_STORAGE
        );
    }
}

我从 4 天前就开始绝望了......

Answer 1

我发现出了什么问题(显然我还有其他问题，但是 x))所以我用的问题

InputStream stream = getContentResolver().openInputStream(
                data.getData());

但我已经这样做了:

final Uri selectedImage = data.getData();

但是你不能两次获取数据，所以我就这样做了:

InputStream stream = getContentResolver().openInputStream(
                selectedImage);

一切顺利!