android - java.lang.IllegalArgumentException : width and height must be > 0 异常

Question

我在 Playstore 上有一个应用程序在极少数设备上生成以下错误。

java.lang.IllegalArgumentException: width and height must be > 0
    at android.graphics.Bitmap.createBitmap(Bitmap.java:829)
    at android.graphics.Bitmap.createBitmap(Bitmap.java:808)
    at android.graphics.Bitmap.createBitmap(Bitmap.java:775)
    at com.my.app.fragments.ImageFragment$MyAsyncTask$1.void run()(SourceFile:209)
    at android.os.Handler.handleCallback(Handler.java:745)
    at android.os.Handler.dispatchMessage(Handler.java:95)
    at android.os.Looper.loop(Looper.java:171)
    at android.app.ActivityThread.main(ActivityThread.java:5454)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)
    at de.robv.android.xposed.XposedBridge.main(XposedBridge.java:102)

错误发生在MyAsyncTask中的onPostExecute这一行

c.drawBitmap(Bitmap.createBitmap(linearLayout.getWidth(), linearLayout.getHeight(), Bitmap.Config.RGB_565), 0, 0, p);

这是我的代码

在我的 ImageFragment 中，在 onCreateView 中，我这样做

    ImageView img = (ImageView) rootView.findViewById(R.id.img);
    final LinearLayout view= (LinearLayout) rootView.findViewById(R.id.view);
    MyAsyncTask asyncTask= new MyAsyncTask(img, view);
    asyncTask.execute(number);

然后在AsyncTask

class MyAsyncTask extends AsyncTask<Integer, Void, Bitmap> {
        private final WeakReference<ImageView> imageViewReference;
        private LinearLayout linearLayout;

        public MyAsyncTask(ImageView imageView, LinearLayout linearLayout) {
            imageViewReference = new WeakReference<>(imageView);
            this.linearLayout = linearLayout;
        }

        // Decode image in background.
        @Override
        protected Bitmap doInBackground(Integer... params) {

            // Code skipped
            return bitmap;
        }

        @Override
        protected void onPostExecute(Bitmap bitmap) {
            if (bitmap != null) {
                final ImageView imageView = imageViewReference.get();
                if (imageView != null) {
                    imageView.setImageBitmap(bitmap);
                    blurred = CommonUtils.fastblur(bitmap, 0.2f, 20);
                    final Bitmap resultBitmap = Bitmap.createBitmap(blurred.getWidth(), blurred.getHeight(), Bitmap.Config.ARGB_8888);

                    final Canvas c = new Canvas(resultBitmap);
                    c.drawBitmap(blurred, 0, 0, null);

                    final Paint p = new Paint();
                    p.setAlpha(127);

                    linearLayout.post(new Runnable() {
                        @Override
                        public void run() {
                            c.drawBitmap(Bitmap.createBitmap(linearLayout.getWidth(), linearLayout.getHeight(), Bitmap.Config.RGB_565), 0, 0, p);
                            // Rest code skipped
                        }
                    });
                }
            }
        }
    }

在阅读了许多关于这个问题的 stackoverflow 帖子后，我发现如果 View 尚未准备好就会发生这种情况，因此它应该与 View 的 post 方法一起使用，并带有您自己的可运行对象。但我不明白为什么它仍然在某些设备上导致此错误，即 Samsung。有人知道如何解决这个问题吗？任何建议将不胜感激。谢谢!!

Answer 1

您的任务在此设备上运行速度太快，LinearLayout 仍未布局。您可以使用 ViewTreeObserver:

ViewTreeObserver vto = linearLayout.getViewTreeObserver(); 
vto.addOnGlobalLayoutListener(new OnGlobalLayoutListener() { 
    @Override 
    public void onGlobalLayout() { 
        linearLayout.getViewTreeObserver().removeGlobalOnLayoutListener(this); 
        int width  = linearLayout.getMeasuredWidth();
        int height = linearLayout.getMeasuredHeight(); 
        c.drawBitmap(Bitmap.createBitmap(width, height, Bitmap.Config.RGB_565), 0, 0, p);
        // Rest code skipped
    }
});