C++ 错误 C2660 : Function does not take 3 arguments

Question

我正在绞尽脑汁想弄清楚。我知道这很简单，但我需要一双新眼睛来弄清楚我错过了什么？

行包含下面的**，从底部开始第 7 行

我收到错误 C2660:“drillOneProblem”:函数不接受 3 个参数。请帮忙!

// Drill into problem
void drillOneProblem()
{
int c, r1, r2; // passed-in parameters
int CorAns; // correct answer
int reply; // user's answer

// Ask first part of question and display first random number
cout << "\nWhat is " << r1;

// Display sign based on user's answer
switch (c)
{
    case '1': cout << " + ";
    CorAns = r1 + r2;
    break;
    case '2': cout << " - ";
    CorAns = r1 - r2;
    break;
    case '3': cout << " * ";
    CorAns = r1 * r2;
    break;
}

// Finish question and display second random number
// Ask answer, validate answer and display message
cout << r2 << " ? ";
cin >> reply;

if (reply == CorAns)
{
cout << "Yes, that is corret. Good job!";
}
else
cout << "No, the correct answer is: " << CorAns << endl << endl;
}

int main()
{
    int c; // user's menu choice
    int r1, r2; // random numbers

    //Display Menu
    displayMenu();

   // Get user's choice and validate if out of range
   c = getMenuChoice();

   // Continue with program if user doesn't quit
   while (c >= 1 && c < SENT)
{
    // Generate random numbers
    Gen2Rand(r1, r2);

    // Display question based on user's menu choice request answer and validate answer. 
    // Display message to show if correct or not correct. If not correct display correct answer
    **drillOneProblem(c, r1, r2);**

    // display menu again and ask for menu choice after problem has been processed, repeat until  
    user quits
    displayMenu();
    c = getMenuChoice();
    } return 0;
}

Answer 1

参数需要在函数声明的括号内声明。

所以这样:

void drillOneProblem()
{
int c, r1, r2; // passed-in parameters

应该是这样的:

void drillOneProblem(int c, int r1, int r2)
{