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java - Android 中使用 Retrofit 2 的 HTTP POST 请求

转载 作者:行者123 更新时间:2023-11-30 00:46:45 28 4
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我正在尝试将 String 发送到服务器,但遇到了问题。

这是我的方法。

ppublic void intervalPost(View view) {
Retrofit retrofit = new Retrofit.Builder()
.baseUrl("http://requestb.in/")
.addConverterFactory(GsonConverterFactory.create())
.build();
PostInterface service = retrofit.create(PostInterface.class);
Call<ResponseBody> call = service.postTime(time2);
call.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
Log.d("Postavke", "Reached onResponse");
if (!response.isSuccess()) {
Log.d("Postavke", "No Success");
}

}

@Override
public void onFailure(Call<ResponseBody> call,Throwable t) {
// Toast for the moment
// Appropriate error handling code should be present here
Toast.makeText(Postavke.this, "Failed !", Toast.LENGTH_LONG).show();
}
});
}

和界面:

public interface PostInterface {
@FormUrlEncoded
@POST("/1b2bqxl1")
Call<ResponseBody> postTime(@Field("interval") String time);

我从微调器中获取字符串 time2:

spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
@Override
public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
String label = spinner.getSelectedItem().toString();
tokens = new StringTokenizer(label, " ");
time = tokens.nextToken().trim();
timeConvert = Integer.parseInt(time);
if (timeConvert == 1 || timeConvert == 2 || timeConvert == 3 || timeConvert == 6 || timeConvert == 12)
timeConvert = timeConvert * 60;
time2 = String.valueOf(timeConvert);
}

想法是当您在微调器中选择间隔时,单击按钮应该将 time2 发送到服务器。

当我运行该应用程序时出现此错误:java.lang.IllegalStateException: Could not execute method for android:onClick

我的问题是如何修复这个错误,还有如果你可以检查 post 方法,我不确定它是否有效。

布局:

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@drawable/bg"
android:orientation="vertical"
>


<TextView
android:text="@string/odaberi_interval"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:id="@+id/odabirintervala"
android:textSize="20sp"
android:layout_marginTop="30dp"
android:layout_marginLeft="30dp"
android:layout_marginRight="20dp"
android:textColor="#148299"
/>

<Spinner
android:id="@+id/spinner"
android:layout_width="125dp"
android:layout_height="wrap_content"
android:layout_marginTop="33dp"
android:layout_toRightOf="@id/odabirintervala"
android:drawSelectorOnTop="true"
></Spinner>

<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Promijeni interval"
android:layout_below="@id/spinner"
android:layout_marginTop="20dp"
android:layout_centerHorizontal="true"
android:onClick="intervalPost"
android:id="@+id/intervalButton"
/>
</RelativeLayout>

最佳答案

从错误中您得到消息“@Field 参数只能与表单编码一起使用。”

这意味着,你需要把@FormUrlEncoded 放在你的界面上

@FormUrlEncoded
@POST("/1gics1o1")
Call<Response> postTime(@Field("interval") String time);

错误“Caused by: android.os.NetworkOnMainThreadException”表示您的网络进程在主线程中的时间太长,因为您没有使用异步方法。尝试改变

  call.execute();

使用入队方法

  call.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
Log.d("Postavke", "Reached onResponse");
if (!response.isSuccess()) {
Log.d("Postavke", "No Success");
}else{
Log.d("Postavke", "responsebody => "+ response.body().toString());
}


}

@Override
public void onFailure(Call<ResponseBody> call,Throwable t) {
// Toast for the moment
// Appropriate error handling code should be present here
Toast.makeText(Postavke.this, "Failed !", Toast.LENGTH_LONG).show();
}
});

关于java - Android 中使用 Retrofit 2 的 HTTP POST 请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41666974/

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