c++ - 为什么模板运算符重载不起作用？

Question

为什么这段代码不打印“operator=”？

#include <iostream>
using namespace std;

class A{
public:
    template<typename T> void operator=(const T& other){
        cout<<"operator="<<endl;
    }
};

int main(){
    A a;
    A b;
    a=b;
}

Answer 1

编译器生成的复制赋值运算符由重载决议选择:

class A{
public:
  A& operator=(A const& other){
    std::cout << "copy assignment\n";
    return *this;
  }
  template<class T>
  void operator=(T const& other){
    std::cout << "templated assignment\n";
  }
};

将打印“复制赋值”并且基本上等于编译器将为您生成的内容(当然不打印)。