MySQL 5.6 程序通过 Workbench 的验证器但无法工作，错误代码 : 1064

Question

该代码正在通过 MySQL Workbench 验证器，但根本不起作用。有人可以帮我解答一下吗？

它所做的只是在执行失败后抛出此错误。

Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'NULL' at line 1

drop procedure if exists dividir_tabla_por_usuario;

delimiter //
create procedure dividir_tabla_por_usuario(tabla varchar(100), columna_usuario varchar(100), columna_fecha varchar(100))
begin
  set @i = 0;
  set @q1 = concat('select count(*) from (select distinct ', columna_usuario ,' from ', tabla , ' order by ', columna_usuario ,' asc) as t1 into @c');
  prepare p1 from @q;
  execute p1;
while @i <= @c do
  set @r = 0;
  set @q2 = concat('select * from ', tabla , ' where ', columna_usuario ,' = (select ', columna_usuario ,' from (select @r:=@r +1 as ord, ', columna_usuario ,' from (select distinct ', columna_usuario ,' from ', tabla , ' order by ', columna_usuario ,' asc) as t2) as t3 where ord = ', @i ,' ) order by ', columna_fecha ,' asc limit 30000'); 
  prepare p2 from @q2;
  execute p2;
  set @i := @i + 1;
end while;
end//
delimiter ;

call dividir_tabla_por_usuario('mytable', 'mycolumn1', 'mycolumn2');

感谢您的关注。

Answer 1

尝试改变:

...
/* prepare p1 from @q; */
PREPARE p1 FROM @q1;
...