android - 如何在 android 中的回收器 View 的每个 3rd 索引上放置 View ？

Question

我有一个回收器 View ，其中有一些字符串，如 0、1、2、3 等等，在同一个回收器 View 中，我想在每个第 3 个索引上放置一个像 imageview 这样的 View 。下面提到的代码工作正常，但问题是 imageview 从 0 索引开始，如序列:- Imageview-->0,1,2--->imageview--->。这里我不想在索引 0 之前显示 ImageView 。

代码:-

 mList = (RecyclerView) findViewById(R.id.dealList);
    layoutManager = new LinearLayoutManager(mContext);
    mList.setLayoutManager(layoutManager);
    mList.setHasFixedSize(true);
    // set divider between items of list
    mList.addItemDecoration(new DividerItemDecoration(mContext, DividerItemDecoration.VERTICAL));
    list = getResources().getStringArray(R.array.list);
    int size = list.length;
    ArrayList<String> newList = new ArrayList<>();
    for (int i = 0; i < size; i++) {
        if (i%2==0){
            newList.add(null);
        }
        newList.add(list[i]);
    }
    adapter = new CMyAdapter(mContext, newList);
    mList.setAdapter(adapter);

适配器代码:-

private Context mContext;
private ArrayList<String> newList;
private static final int CONTENT_TYPE = 0;
private static final int AD_TYPE = 1;

public CMyAdapter(Context context, ArrayList<String> list) {
    this.mContext = context;
    this.newList = list;
}

@Override
public ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
    ViewHolder holder = null;
    if (viewType == AD_TYPE) {
        View adView = LayoutInflater.from(parent.getContext()).inflate(R.layout.view2, parent, false);
        holder = new AdViewHolder(adView);
    } else {
        View itemView = LayoutInflater.from(parent.getContext()).inflate(R.layout.view1, parent, false);
        holder = new ItemViewHolder(itemView);
    }
    return holder;
}

@Override
public int getItemViewType(int position) {
    if (newList.get(position) == null) {
        return AD_TYPE;
    } else {
        return CONTENT_TYPE;
    }

}

@Override
public void onBindViewHolder(ViewHolder holder, int position) {
    if (newList.get(position) == null) {
        AdViewHolder adViewHolder = (AdViewHolder) holder;
        adViewHolder.m_dummyImage.setImageResource(R.mipmap.ic_launcher_round);
    } else {
        ItemViewHolder itemViewHolder = (ItemViewHolder) holder;
        itemViewHolder.m_Text.setText(newList.get(position));
    }
}

@Override
public int getItemCount() {
    return newList.size();
}

class ViewHolder extends RecyclerView.ViewHolder {
    ViewHolder(View itemView) {
        super(itemView);


    }
}

private class ItemViewHolder extends ViewHolder {
    TextView m_Text;

    ItemViewHolder(View itemView) {
        super(itemView);
        m_Text = (TextView) itemView.findViewById(R.id.textDemo);
    }
}

private class AdViewHolder extends ViewHolder {
    ImageView m_dummyImage;

    AdViewHolder(View v) {
        super(v);
        m_dummyImage = (ImageView) itemView.findViewById(R.id.adImage);
    }
}

Answer 1

在if条件中加入(i!=0)

if (i%2==0 && i!=0){
        newList.add(null);
    }