gpt4 book ai didi

android - Parcelable 从数组中获取巨大的无限项目直到 OOM

转载 作者:行者123 更新时间:2023-11-30 00:30:57 25 4
gpt4 key购买 nike

我正在使用 Parcelable 在 fragment 之间进行通信。一切都运行良好,但有时当 Android 终止应用程序进程以释放内存并且用户返回到应用程序时,Parcelable 从数组中获取大量项目,例如几百万个项目而不是 2-3 个,当然它会抛出 OOM。我想 CREATOR 有问题,但我无法处理它。parcelable 的代码由父类(super class)和子类以及我感兴趣的项目类组成:

基类:

 public abstract class BaseRs implements Parcelable {

private String token;
private String msgAlert;
private String simpleMsg;
private AdsObj adsObj;
private Map<String, String> mapSettings;

//getters & setters

public BaseRs() {
}


protected BaseRs(Parcel in) {
token = in.readString();
msgAlert = in.readString();
simpleMsg = in.readString();
adsObj = in.readParcelable(AdsObj.class.getClassLoader());
mapSettings = MapParcelable.readParcelable(in);
}

@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(token);
dest.writeString(msgAlert);
dest.writeString(simpleMsg);
dest.writeParcelable(adsObj, flags);
MapParcelable.writeToParcel(dest, mapSettings);
}

}

子类

public class GetSalesItemsRs extends BaseRs {

private SaleCoinItem[] coinPacksArray;

//getters+ setters


protected GetSalesItemsRs(Parcel in) {
super(in);
coinPacksArray = in.createTypedArray(SaleCoinItem.CREATOR);
}

@Override
public void writeToParcel(Parcel dest, int flags) {
super.writeToParcel(dest, flags);
dest.writeTypedArray(coinPacksArray, flags);
}

@Override
public int describeContents() {
return 0;
}

public static final Creator<GetSalesItemsRs> CREATOR = new Creator<GetSalesItemsRs>() {
@Override
public GetSalesItemsRs createFromParcel(Parcel in) {
return new GetSalesItemsRs(in);
}

@Override
public GetSalesItemsRs[] newArray(int size) {
return new GetSalesItemsRs[size];
}
};
}

和我感兴趣的对象

public class SaleCoinItem implements Parcelable {

private int amount;
private double price;
private int sortOrder;

//getters & setters

protected SaleCoinItem(Parcel in) {
amount = in.readInt();
price = in.readDouble();
sortOrder = in.readInt();
}

@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeInt(amount);
dest.writeDouble(price);
dest.writeInt(sortOrder);
}

@Override
public int describeContents() {
return 0;
}

public static final Creator<SaleCoinItem> CREATOR = new Creator<SaleCoinItem>() {
@Override
public SaleCoinItem createFromParcel(Parcel in) {
return new SaleCoinItem(in);
}

@Override
public SaleCoinItem[] newArray(int size) {
return new SaleCoinItem[size];


}
};
}

parcel Map 的功能 - 也许这里是错误 ;)

public class MapParcelable {

public static void writeToParcel(Parcel out, Map<String, String> map) {
if (map != null) {
out.writeInt(map.size());
for (Map.Entry<String, String> entry : map.entrySet()) {
out.writeString(entry.getKey());
out.writeString(entry.getValue());
}
}
}

public static Map<String, String> readParcelable(Parcel parcel) {
Map<String, String> map = new HashMap<String, String>();
int size = parcel.readInt();
for (int i = 0; i < size; i++) {
String key = parcel.readString();
String value = parcel.readString();
map.put(key, value);
}

return map;


}

}

我在 onCreateView 方法中获取了 parcelable obj :

GetSalesItemsRs mGetSalesItemsRs = getArguments().getParcelable(KEY_PARCEL);

最佳答案

我认为问题在于,如果 Map 为 null,则您不会将大小字段写入 Parcel,但当您读取它时,您总是会读取大小字段,并且它最终可能会读取一些随机值。所以或者你把代码改成

if (map != null) {
out.writeInt(map.size());
for (Map.Entry<String, String> entry : map.entrySet()) {
out.writeString(entry.getKey());
out.writeString(entry.getValue());
}
}else{
out.writeInt(0);
}

并且在重新创建类时永远不会得到空值,或者您创建另一个 bool 字段“hasMap”并始终写入那个

关于android - Parcelable 从数组中获取巨大的无限项目直到 OOM,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44389044/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com