javascript - 如何在 Grails 中接收 Angular $http post 多部分表单数据

Question

如何从 Grails 接收 Angular $http post 多部分表单数据。在这里，我将多部分表单数据从 Angular Controller 发送到 Grails。我是 Grails 的新手。

任何人都可以指导我检索边界数据。我也不知道接收带有一些输入数据的图像文件数据的正确形式。

浏览器网络控制台中的请求 header :

Provisional headers are shown
Accept:application/json, text/plain, */*
Content-Type:multipart/form-data; boundary=----    
WebKitFormBoundary0p6R8BecvYqzcbMK
Origin:file://
User-Agent:Mozilla/5.0 (iPhone; CPU iPhone OS 7_0 like Mac OS X; en-us)        
AppleWebKit/537.51.1 (KHTML, like Gecko) Version/7.0 Mobile/11A465     Safari/9537.53
Request Payload
------WebKitFormBoundary0p6R8BecvYqzcbMK
Content-Disposition: form-data; name="rackImage"; filename="PhoneGap.png"
Content-Type: image/png


------WebKitFormBoundary0p6R8BecvYqzcbMK
Content-Disposition: form-data; name="storeNo"

HD1304

------WebKitFormBoundary0p6R8BecvYqzcbMK
Content-Disposition: form-data; name="rackQty"

12
------WebKitFormBoundary0p6R8BecvYqzcbMK--

Answer 1

给你。只需在您的 Controller 中写入以下内容:

class MyController {

    def upload() {
        def multipartFile = params.rackImage

        InputStream is
        FileOutputStream fos

        byte[] fileRead = new byte[1024]
        File tempFile

        try {
            is = multipartFile.getInputStream()
            String fileName = multipartFile.getOriginalFilename()

            String path = "./"

            fileName = fileName.replaceAll("[^a-zA-Z0-9//._-]+", "").toLowerCase()

            tempFile = new File(path + "" + fileName)
            fos = new FileOutputStream(tempFile);
            int i = is.read(fileRead)
            while (i != -1) {
                fos.write(fileRead, 0, i);
                i = is.read(fileRead);
            }
        } catch (FileNotFoundException e) {
            log.error "Exception uploading", e
        } catch (IOException e) {
            log.error "Exception uploading", e
        } finally {
            fos?.close()
            is?.close()
        }

        // Now access the File: "tempFile"
    }
}