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php - 如何在 Codeigniter 中生成此 MySQL 代码?

转载 作者:行者123 更新时间:2023-11-30 00:01:28 27 4
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这是我的 MySQL 代码。我是 Codeigniter 的新手。

SELECT
a.school_code,
b.Us_News_Ranking,
b.School_Name,
COUNT( * ) AS LSN_APPLICATIONS,
COUNT( a.status ) AS STATUS,
COUNT(
CASE
WHEN a.status = 'w'
THEN a.status
END
) AS accp_rate,
COUNT(
CASE
WHEN a.status = 'Intend_to_apply'
THEN a.status
END
) AS accp_rate2,
AVG( CAST( a.Med_LSAT AS DECIMAL( 12, 2 ) ) ) AS MEd_LSAT,
AVG( CAST( a.Med_GPA AS DECIMAL( 12, 2 ) ) ) AS MEd_GPA
FROM user_application a, lawscools b
WHERE a.school_code = b.school_code
GROUP BY school_code
LIMIT 0 , 30

最佳答案

您可以使用查询功能

$this->db->query('SQL_CODE');

嗯..我想还有另一种方法,但为什么不呢? :)

关于php - 如何在 Codeigniter 中生成此 MySQL 代码?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24998307/

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