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php - 自动完成地址表跨两个表

转载 作者:行者123 更新时间:2023-11-29 23:56:18 25 4
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这里是新手,需要帮助。

我使用 http://www.jensbits.com/2010/03/29/jquery-ui-autocomplete-widget-with-php-and-mysql/ 中的代码

它在某些领域工作得很好。我的问题是,我将国家和州存储在另一个表中,并且在“if ($address_query->num_rows) {”周围出现“尝试获取非对象的属性”错误。

autocomplete.php

$dbhost = 'SERVER';
$dbuser = 'USERNAME';
$dbpass = 'PASSWORD';
$dbname = 'DATABASE_NAME';

try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
}
catch(PDOException $e) {
echo $e->getMessage();
}

$return_arr = array();
if ($conn)
{
$ac_term = "%".$_GET['term']."%";
$address_query = "SELECT * FROM address where customer_id = '" . $customer_id . "' AND (firstname like :term OR lastname like :term) LIMIT 10";
if ($address_query->num_rows) { // got "Trying to get property of non-object" error
$country_query = "SELECT * FROM country WHERE country_id = '" . (int)$address_query->row['country_id'] . "'";

if ($country_query->num_rows) {
$country = $country_query->row['name'];
$iso_code_2 = $country_query->row['iso_code_2'];
} else {
$country = '';
$iso_code_2 = '';
}

$zone_query = "SELECT * FROM zone WHERE zone_id = '" . (int)$address_query->row['zone_id'] . "'";

if ($zone_query->num_rows) {
$zone = $zone_query->row['name'];
$zone_code = $zone_query->row['code'];
} else {
$zone = '';
$zone_code = '';
}
$result = $conn->prepare($address_query);
$result->bindValue(":term",$ac_term);
$result->execute();

/* Retrieve and store in array the results of the query.*/
while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
$return_arr [] = array(

'label' => $row['firstname'] .' '. $row['lastname'] .' '. $row['company'] .' '. $row['city'] .' '. $row['postcode'],
'value' => $row['firstname'] .' '. $row['lastname'],
'Company' => $row['company'],
'Country' => $row['iso_code_2'],
'postCode' => $row['postcode'],

);
}


}

echo json_encode($return_arr);
flush();
?>

如果我删除代码

if ($query->num_rows) { // got "Trying to get property of non-object" error
$country_query = "SELECT * FROM country WHERE country_id = '" . (int)$address_query->row['country_id'] . "'";

if ($country_query->num_rows) {
$country = $country_query->row['name'];
$iso_code_2 = $country_query->row['iso_code_2'];
} else {
$country = '';
$iso_code_2 = '';
}

$zone_query = "SELECT * FROM zone WHERE zone_id = '" . (int)$address_query->row['zone_id'] . "'";

if ($zone_query->num_rows) {
$zone = $zone_query->row['name'];
$zone_code = $zone_query->row['code'];
} else {
$zone = '';
$zone_code = '';
}

它适用于姓名、公司和邮政编码。顺便说一句,国家和州字段是下拉选择形式。

任何帮助将不胜感激!

最佳答案

您的 $address_query 不是一个对象,而是一个字符串,因此您会收到错误“尝试获取非对象的属性”

要访问 pdo 对象,您需要通过您创建的 $conn 访问它

$conn = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);

$address_query = "SELECT * FROM address where customer_id = '" . $customer_id . "' AND (firstname like :term OR lastname like :term) LIMIT 10";

$result = $conn->prepare($address_query);
$result->execute(array(':term'-> $term));

if ($result->rowCount()){

$conn 是对象,$address_query 是字符串,在字符串中还有一个占位符 :term 您需要在执行函数中为 sql 语句设置该值,这是在中查找所有 :term字符串并将其替换为值

你的sql也出了问题,因为你知道表中的国家ID,你应该加入表

您的代码应如下所示:

$dbhost = 'SERVER';
$dbuser = 'USERNAME';
$dbpass = 'PASSWORD';
$dbname = 'DATABASE_NAME';

try {
$conn = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass);
}
catch(PDOException $e) {
echo $e->getMessage();
}

$return_arr = array();
if ($conn)
{
$ac_term = "%".$_GET['term']."%";
$address_query = "SELECT * FROM address LEFT JOIN country address.country_id = country. country_id ON where address.customer_id = '" . $customer_id . "' AND (address.firstname like :term OR address.lastname like :term) LIMIT 10";

$result = $conn->prepare($address_query);
$result->bindValue(":term",$ac_term);
$result->execute();

/* Retrieve and store in array the results of the query.*/
while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
$return_arr [] = array(

'label' => $row['firstname'] .' '. $row['lastname'] .' '. $row['company'] .' '. $row['city'] .' '. $row['postcode'],
'value' => $row['firstname'] .' '. $row['lastname'],
'Company' => $row['company'],
'Country' => $row['iso_code_2'],
'postCode' => $row['postcode'],

);
}}

关于php - 自动完成地址表跨两个表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25319675/

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