android - 如何获得按钮在屏幕上的左右角位置？

Question

我正在尝试获取 View 位置(右上角位置和左下角位置)并在 View 的右侧或左侧显示自定义对话框，但我没有获得 View 的确切位置。这是我的代码

    int x=view.getLeft()+  (view.getHeight()*4);
    int y= view.getBottom()+(view.getWidth()*2);
    showDialog(x,y,Gravity.TOP,Gravity.LEFT);`  

    public void showDialog(int x, int y,int gravity_y,int gravity_x){
    final Dialog dialog  = new Dialog(this, R.style.ActivityDialog);
    dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
    dialog.getWindow().setBackgroundDrawable(new ColorDrawable(Color.WHITE));
    dialog.setContentView(R.layout.cofirm_sell);
    dialog.setCanceledOnTouchOutside(false);
    WindowManager.LayoutParams wmlp = dialog.getWindow().getAttributes();
    dialog.getWindow().getAttributes().windowAnimations=R.style.DialogTheme;
    wmlp.gravity = gravity_y | gravity_x;
    wmlp.x = x;
    wmlp.y = y;
    ImageButton close=(ImageButton)dialog.findViewById(R.id.close);
    close.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            dialog.dismiss();
        }
    });
    dialog.show();

我要这个

Answer 1

检查这个:

    int[] outLocation = new int[2];
    view.getLocationOnScreen(outLocation);
    Rect rect = new Rect(
            outLocation[0],
            outLocation[1],
            outLocation[0] + view.getWidth(),
            outLocation[1] + view.getHeight());
    //right upper corner rect.right,rect.top 
    //left bottom corner rect.left,rect.bottom