java - Android 房间持久性查询返回空值

Question

我目前正在学习如何使用 Android Room Persistence 库。以下代码在尝试查询 (findById) 以获取绑定(bind)到 int (ID) 的已保存 boolean 值时遇到问题。尝试这样做时，它反复出现 null。这里有我忽略的问题吗？有人可以指出我在这里做错事的正确方向吗？谢谢。

Collection 电影道

@Dao
public interface FavoriteMovieDao {
    @Query("SELECT * FROM favoritemovie")
    List<FavoriteMovie> getAll();

    @Query("SELECT * FROM favoritemovie WHERE id IN (:ids)")
    List<FavoriteMovie> loadAllByIds(int[] ids);

    @Query("SELECT * FROM favoritemovie WHERE id LIKE :id LIMIT 1")
    FavoriteMovie findById(int id);

    @Insert(onConflict = OnConflictStrategy.REPLACE)
    void insert(FavoriteMovie movie);

    @Delete
    void delete(FavoriteMovie movie);
}

FavoriteMovie.java(实体)

@PrimaryKey
private int id;
public int getId(){
    return id;
}

public void setId(int id){
    id = id;
}

@ColumnInfo(name = "favorite")
private boolean favorite;

public boolean getFavorite(){
    return favorite;
}

public void setFavorite(boolean favorite){
    favorite = favorite;
}

public void FavoriteMovie(int id, boolean favorite) {
    this.id = id;
    this.favorite = favorite;
}

在执行插入之前尝试查询

db = Room.databaseBuilder(getApplicationContext(),
AppDatabase.class, "database-name").allowMainThreadQueries().build();
if (db.favoriteMovieDao().findById(classId) == null) {
    FavoriteMovie fm = new FavoriteMovie();
    fm.setId(classId);
    fm.setFavorite(true);
    db.favoriteMovieDao().insert(fm);
}

应用数据库.java

@Database(entities = {FavoriteMovie.class}, version = 1)
public abstract class AppDatabase extends RoomDatabase {
    public abstract FavoriteMovieDao favoriteMovieDao();
}

Answer 1

您的setId 方法没有引用字段id。您的参数会影响您的领域。我认为您应该改用 this.id。