javascript - GraphQL 解析 GraphQLObjectType

Question

我正在使用 express-graphql以及以下查询:

invitations {
    sent 
    received
}

模式定义(简化)如下:

const InvitationType = new GraphQLObjectType({
    name: 'InvitationType',
    description: 'Friends invitations',
    fields: {
        sent: {
            type: new GraphQLList(GraphQLString),
            description: 'Invitations sent to friends.',
            resolve() {
             return ['sentA'];
            }
        },
        received: {
            type: new GraphQLList(GraphQLString),
            description: 'Invitations received from friends.',
            resolve() {
             return ['receivedA', 'receivedB'];
            }
        }
    }
});

// Root schema
const schema = new GraphQLSchema({
    query: new GraphQLObjectType({
      name: 'RootQueryType',
      fields: {
          invitations: {
              type: InvitationType // no resolve() method here.
          }
      }
    })
});

但是 resolve 方法永远不会为 sent 和 received 字段调用。上面的查询返回:

{data: {invitations: {sent: null, received: null}}}

有没有什么方法可以解析嵌套字段(sent 和 received)而不用在父级(邀请) 字段？

Answer 1

这对我有用!根据GraphQL Documentation , 如果 resolve 方法返回非标量，则执行将继续。所以下面的代码有效:

// Root schema
const schema = new GraphQLSchema({
    query: new GraphQLObjectType({
      name: 'RootQueryType',
      fields: {
        invitations: {
          type: InvitationType,
          resolve: () => ({}) // Resolve returns an object.
        }
      }
    })
});

希望这对您有所帮助。干杯!