PHP - 从函数返回数组

Question

我正在使用以下函数(prize.php)提交表单:

loadmodule('validate'); //This just loads the validate.php function.
    $validate = new Validate;
if($_POST)
    {
        $validateForm = $validate->validateForm();


        switch($validateForm)
        {

                case 1:
                    $error = 'You\'re not logged in..';
                    $stop = true;
                break;

                //If no error = success.    
                if($validateForm['code'] == "100"){
                    $won = $val['prize'];
                    $type = $val['type'];
                    $success = 'You have won! The prize was '.$won.' '.$type.'';
                    die($success);
                }


        }
            die($error);
    }

这是验证表单的函数(validate.php):

function validate()
                {


                    global $userdata;

                    if(!is_array($userdata))
                        return 1; // User not logged in - return error code one.

                    //If no error, lets show a success message.
                    $prize = "100";
                $text = "dollars";
                    return array("code"=>"100","prize"=>"$prize","type"=>"$text");

                    }//If won



                }

上面的代码返回:

Notice: Undefined variable: error in /home/.../public_html/pages/prize.php on line 27

尽管如此，它不应该在那里抛出错误，因为 die($success) 应该由代码 100 触发。

我做错了什么？

Answer 1

$error = '';
$stop = false;
switch($validateForm){
            case 1:
                $error = 'You\'re not logged in..';
                $stop = true;
            break;
}


            //If no error = success.    
            if($validateForm['code'] == "100"){
                $won = $val['prize'];
                $type = $val['type'];
                $success = 'You have won! The prize was '.$won.' '.$type.'';
                die($success);
            }

第一个猜测是 if($validateForm['code'] == "100"){ 被设置在开关之外。

$validateForm = $validate->validateForm();

返回一个数组..稍后当 $validateForm 是一个数组时，您将在 switch 中执行 if ($validateForm==1) 。

使用简单的 is_array() if 语句可能比使用整个 switch 更幸运