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javascript - 火箭在突变后不会改变方向

转载 作者:行者123 更新时间:2023-11-29 23:38:58 26 4
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我对一些机器学习的东西有疑问。在第一代火箭之后没有变异,只是遵循相同的路径。如您所见,我尝试了不同的方法来解决这个问题,但它们都不起作用。我在 openprocessing.org 中写了这个,但也尝试在本地进行。我没有看到问题,但我认为它在 Rocket 构造函数中。

var rockets = [];
var bf = -1;
var br;

function setup() {
createCanvas(windowWidth, windowHeight);
background(100);
noStroke();
fill(255, 50);
frameRate(10);
target = createVector(width, height / 2);
for (var i = 0; i < 10; i++) {
rockets.push(new Rocket());
}
}

function draw() {
background(100);
ellipse(width / 2, height / 2, 40, 40);
ellipse(width - 10, height / 2, 40, 40);
for (i = 0; i < rockets.length; i++) {
rockets[i].show();
//console.log(rockets[i].pos.y);
if (!rockets[i].killed) {
rockets[i].applyForce(); //it is a fittness counter inside
}
}
//console.log(rockets);
if (rockets[0].counter >= rockets[0].route.length) {
findBest();
respawn();
}
}

function respawn() {
var news = mutate(br);
for (var i = 0; i < 10; i++) {
rockets.push(new Rocket());
//console.log(rockets);
rockets[i].route = news[i];
}
}

function findBest() {
for (var i = 0; i < rockets.length; i++) {
//console.log(rockets[i].fittness);
if (rockets[i].fittness > bf) {
br = rockets[i].route;
bf = rockets[i].fittness;
}
}
rockets = [];
}

function mutate(arr) {
var news = [];
for (var i = 0; i < 10; i++) {
var tempArr = arr;
tempArr[floor(random(arr.lenth))] = p5.Vector.random2D().setMag(30);
news.push(tempArr);
}
return news;
}

function Rocket(a) {
this.pos = createVector(width / 2, height / 2);
this.route = [];
this.counter = 0;
this.fittness = 0;
this.killed = false;
//console.log(a);
if (!a) {
for (var i = 0; i < 20; i++) {
this.route.push(p5.Vector.random2D());
this.route[i].setMag(20);
//console.log("!A");
// console.log(i);
}
} else {
// this is not used
this.route = a;
// for(var i = floor(random(a.length-1)); i<a.length; i++) {
//console.log(this.route[i]);
b = floor(random(this.route.length - 1));
console.log("before: ", this.route[b]);
this.route[b] = p5.Vector.random2D().setMag(30);
//this.route[i].rotate(0.2*pow(-1, i));
console.log("after: ", this.route[b]);
//}
}

//console.log(mutate(this.route));
this.applyForce = function() {
if (this.counter == this.route.length - 1) {
this.countFittness();
//console.log(this.fittness);
this.killed = true;
}
this.pos.add(this.route[this.counter]);
this.counter++;
}
this.countFittness = function() {

this.fittness = 1 / this.pos.dist(target) * 100;
//console.log(this.fittness);
}
this.show = function() {
ellipse(this.pos.x, this.pos.y, 10, 10);

}
}
<html>

<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/0.5.12/p5.js"></script>
</head>

</html>

最佳答案

不错的代码。您的 mutate 函数似乎有错误:

function mutate(arr) {
var news = [];
for (var i = 0; i < 10; i++) {
var tempArr = arr;
tempArr[floor(random(arr.length))] = p5.Vector.random2D().setMag(30);
news.push(tempArr);
}
return news;
}

当你使用

var tempArr = arr;

在 javascript 中,您不会获得数组的副本。两个数组将指向相同的引用。当你改变一个时,原来的也会改变。这样最终火箭的所有路线都会相同。

尝试...

var tempArr = arr.slice();

slice() 操作克隆数组并返回对新数组的引用。

同样的函数中还有一个小错别字。我觉得应该是……

tempArr[floor(random(arr.length))] = p5.Vector.random2D().setMag(30);

关于javascript - 火箭在突变后不会改变方向,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45751718/

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