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php - 如何使搜索栏中的链接转到不同的页面?

转载 作者:行者123 更新时间:2023-11-29 23:30:35 25 4
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我目前有一个有点工作的搜索栏,它按照我想要的方式工作,我只是想知道是否可以添加指向不同搜索项目的链接?现在,任何搜索的内容都会重定向到“Session.php”,例如,如果有人搜索“Home”,我是否可以显示结果,然后用户可以单击“Home.php”?谢谢!

Search.php代码:

<?php 
//--- Authenticate code begins here ---
session_start();
//checks if the login session is true
if(!isset($_SESSION['sess_user'])){
header("location:index.php");
}
$username = $_SESSION['sess_user'];

// --- Authenticate code ends here ---
?>

<link rel="stylesheet" type="text/css" href="../css/style1.css">
<?php
mysql_connect("localhost", "root", "") or die("Error connecting to database: ".mysql_error());
mysql_select_db("aha") or die(mysql_error());
?>
<html>
</html>

退出

    <head>
<title>Search results</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" href="style.css"/>
</head>
<body>
<?php
$query = $_GET['query'];


$min_length = 3;


if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then

$query = htmlspecialchars($query);
// changes characters used in html to their equivalents, for example: < to &gt;

$query = mysql_real_escape_string($query);
// makes sure nobody uses SQL injection

$raw_results = mysql_query("SELECT * FROM articles
WHERE (`title` LIKE '%".$query."%') OR (`text` LIKE '%".$query."%')") or die(mysql_error());

// * means that it selects all fields, you can also write: `id`, `title`, `text`
// articles is the name of our table

// '%$query%' is what I'm looking for, % means anything, for example if $query is Hello
// it will match "hello", "Hello man", "gogohello", if you want exact match use `title`='$query'
// or if you want to match just full word so "gogohello" is out use '% $query %' ...OR ... '$query %' ... OR ... '% $query'

if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following

while($results = mysql_fetch_array($raw_results)){
// $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop



echo "<a href='../pages/session.php'><h3>{$results['title']}</h3></a><p>{$results['text']}</‌​p>";



}


}
else{ // if there is no matching rows do following
echo ("<br><br>No results</br></br>");
}

}

else{ // if query length is less than minimum
echo ("</br></br>Minimum length is</br></br> ".$min_length);
}

?>


</body>

<br>
<br>
<a class="btn btn-search" type="button" href="index.php" >Search Again</a>
</br>
</br>




DB FOR ARTICLE:

http://puu.sh/ctUUq/2f73509cf2.png

谢谢!

最佳答案

您必须将每条记录的页面名称存储在数据库中,然后通过查询检索它。

考虑到您将其存储在 SQL 表上名为“page_name”的列中,请根据用户的查询更改此行以指向正确的页面:

echo "<a href='../pages/{$results['page_name']}'><h3>{$results['title']}</h3></a><p>{$results['text']}</‌​p>";

关于php - 如何使搜索栏中的链接转到不同的页面?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26605456/

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