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php - 仅限页面显示

转载 作者:行者123 更新时间:2023-11-29 23:24:08 25 4
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我想问是否有一个解决方案可以通过 PHP 查询 MySQL 数据库,只加载一组结果中的 1 页,但在分页中仍然显示为 [1] 2 3 4 5... 所以当用户单击第二页,例如 1 [2] 3 4 5...,然后加载第二页,依此类推?

我的数据库非常庞大,一次加载 1000 个页面会消耗大量带宽,并且该过程需要大约 50 秒,这太长了。

我需要找到一个解决方案来缩短加载时间。我的实际查询如下:

$start = ($page - 1) * $per_page;
$query = '
SELECT *, (MATCH(url) AGAINST('.$qo1.''.$out.''.$qo2.' IN BOOLEAN MODE) * 0.015 + MATCH(title) AGAINST ('.$qo1.''.$out.''.$qo2.' IN BOOLEAN MODE) * 0.015 + MATCH(description,body) AGAINST('.$qo1.''.$out.''.$qo2.' IN BOOLEAN MODE) * 0.040 + MATCH(keywords) AGAINST ('.$qo1.''.$out.''.$qo2.' IN BOOLEAN MODE) * 0.030) AS relevance
FROM table
WHERE MATCH(url, title, description, body, keywords) AGAINST ('.$qo1.''.$out.''.$qo2.' IN BOOLEAN MODE)
ORDER BY relevance '.$ord.' LIMIT '.$start.','.$per_page.'';

问候

最佳答案

这个脚本为我指明了构建分页的正确方向,只允许按显示的页面接收结果。

<?php 
// Script and tutorial written by Adam Khoury @ developphp.com // Line by line explanation : youtube.com/watch?v=T2QFNu_mivw
include_once("mysqli_connection.php");
// This first query is just to get the total count of rows
$sql = "SELECT COUNT(id) FROM testimonials WHERE approved='1'";
$query = mysqli_query($db_conx, $sql);
$row = mysqli_fetch_row($query);
// Here we have the total row count
$rows = $row[0];
// This is the number of results we want displayed per page
$page_rows = 10;
// This tells us the page number of our last page
$last = ceil($rows/$page_rows);
// This makes sure $last cannot be less than 1
if($last < 1){ $last = 1; }
// Establish the $pagenum variable
$pagenum = 1;
// Get pagenum from URL vars if it is present, else it is = 1
if(isset($_GET['pn'])){ $pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']); }
// This makes sure the page number isn't below 1, or more than our
$last page if ($pagenum < 1)
{ $pagenum = 1; }
else if ($pagenum > $last)
{ $pagenum = $last; }
// This sets the range of rows to query for the chosen $pagenum
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
// This is your query again, it is for grabbing just one page worth of rows by applying $limit
$sql = "SELECT id, firstname, lastname, datemade FROM testimonials WHERE approved='1' ORDER BY id DESC $limit";
$query = mysqli_query($db_conx, $sql);
// This shows the user what page they are on, and the total number of pages
$textline1 = "Testimonials (<b>$rows</b>)"; $textline2 = "Page <b>$pagenum</b> of <b>$last</b>";
// Establish the $paginationCtrls variable
$paginationCtrls = '';
// If there is more than 1 page worth of results
if($last != 1){
/* First we check if we are on page one. If we are then we don't need a link to the previous page or the first page so we do nothing. If we aren't then we generate links to the first page, and to the previous page. */
if ($pagenum > 1)
{ $previous = $pagenum - 1;
$paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$previous.'">Previous</a> &nbsp; &nbsp; ';
// Render clickable number links that should appear on the left of the target page number
for($i = $pagenum-4; $i < $pagenum; $i++)
{ if($i > 0)
{ $paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$i.'">'.$i.'</a> &nbsp; ';
}
}
}
// Render the target page number, but without it being a link
$paginationCtrls .= ''.$pagenum.' &nbsp; ';
// Render clickable number links that should appear on the right of the target page number
for($i = $pagenum+1; $i <= $last; $i++)
{ $paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$i.'">'.$i.'</a> &nbsp; ';
if($i >= $pagenum+4){ break; }
}
// This does the same as above, only checking if we are on the last page, and then generating the "Next"
if ($pagenum != $last)
{ $next = $pagenum + 1;
$paginationCtrls .= ' &nbsp; &nbsp; <a href="'.$_SERVER['PHP_SELF'].'?pn='.$next.'">Next</a> ';
}
}
$list = '';
while($row = mysqli_fetch_array($query, MYSQLI_ASSOC))
{ $id = $row["id"];
$firstname = $row["firstname"];
$lastname = $row["lastname"];
$datemade = $row["datemade"];
$datemade = strftime("%b %d, %Y", strtotime($datemade));
$list .= '<p><a href="testimonial.php?id='.$id.'">'.$firstname.' '.$lastname.' Testimonial</a> - Click the link to view this testimonial<br>Written '.$datemade.'</p>';
}
// Close your database connection
mysqli_close($db_conx);
?>

关于php - 仅限页面显示,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27087618/

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