PHP 在循环表内提交

Question

我有一个 foreach 循环，可以在表中输出我的产品。代码如下所示:

<table class="table table-striped table-bordered table-hover" id="sample_2">
<thead>
<tr>
<th>ID</th>
<th>Product Name</th>
<th>Quantity</th>
<th style="width: 9%;"></th>
</tr>
</thead>
<tbody>
<?php foreach ($inputs as $package){
?>
<form action="" method="post">
<tr>
<td><?php echo $package->id; ?></td>
<td><?php echo $package->name; ?></td>
<td><input type="text" name="quantity" placeholder="Quantity for <?php echo $package->name; ?>" class="form-control"></td>
<td style="text-align: center;"><button name="submit" type="submit" id="submit" class="btn blue"><i class="fa fa-check"></i> submit</button></td>
</tr>
</form>
<?php }
?>
</tbody>
</table>

好吧，我现在需要创建一些东西来将字段插入到 mysql 表中。但是我如何获得 $package->id, $package->name，它们只是 echo 的？我需要将其插入其中:

CREATE TABLE IF NOT EXISTS `shop_packages` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `productid` int(11) NOT NULL,
  `quantity` int(11) NOT NULL,
  `worker` varchar(265) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

提交1的代码。

if (isset($_POST['submit'])) {
$productid = $_POST['id'];
$productname = $_POST['name'];
$quantity = $_POST['quantity'];
$worker = $user['name'];
$workerid = $user['id'];
$result = $user->add_packages($productid,$productname,$quantity,$worker,$workerid);
}

Print_r($_POST['包'])

Array ( [0] => Array ( [id] => 1 ) [1] => Array ( [name] => Maxizoo Spåner 5 kg ) [2] => Array ( [quantity] => ) [3] => Array ( [id] => 4 ) [4] => Array ( [name] => Minihemp 4 kg. ) [5] => Array ( [quantity] => ) [6] => Array ( [id] => 5 ) [7] => Array ( [name] => Maxizoo Hø 2 kg. ) [8] => Array ( [quantity] => 2 ) [9] => Array ( [id] => 6 ) [10] => Array ( [name] => Maxizoo Halm 2 kg ) [11] => Array ( [quantity] => 1 ) )

更新:

if (isset($_POST['submit'])) {

foreach ($_POST['package'] as $p){

    $productid = $p['id'];
    $productname = $p['name'];
    $quantity = $p['quantity'];

    }

$worker = $user['name'];
$workerid = $user['id'];
$result = $user->add_packages($productid,$productname,$quantity,$worker,$workerid);
}

Answer 1

您需要通过表单发送它们，例如使用隐藏输入。

<form action="" method="post">
    <table> 
        <tr>
            <td><?php echo $package->id; ?></td>
            <td><?php echo $package->name; ?></td>
            <td><input type="text" name="quantity" placeholder="Quantity for <?php echo $package->name; ?>" class="form-control"></td>
            <td style="text-align: center;">
                <input type="hidden" name="package_name" value="<?php echo $package->name; ?>"> 
                <input type="hidden" name="package_id" value="<?php echo $package->id; ?>"> 
                ^^
                <button name="submit" type="submit" id="submit" class="btn blue"><i class="fa fa-check"></i> submit</button>
            </td>
        </tr>
    </table>
</form>

那么，您使用 TR 和 TD，它们应该只在一个表中，所以我也添加了一个表。