php - MySQL SELECT WHERE id = array()

Question

我试图将一个数组插入到 SELECT WHERE id = array() 中，并试图在表格中显示结果，我可以获得一行数据，第一支球队的名称、获胜和失败，但其余的4 支球队没有出现。我试图显示 id 等于数组的所有球队。

$tournament = mysql_query("SELECT * FROM `tournaments` WHERE `id` = ".((int)$slug[1])." LIMIT 1");
    if (mysql_num_rows($tournament) > 0) {
        $tournament = mysql_fetch_assoc($tournament);
    }
    //array is equal to 273,287,234,423,124
    $teamx = array();
    $teamx[] = $tournament['teams'];

    $tteams = mysql_query("SELECT * FROM `teams` WHERE `id` IN (" . implode(',', array_map('intval', $teamx)) . ") LIMIT 128");
    if (mysql_num_rows($tteams) > 0) {
        $tteams = mysql_fetch_assoc($tteams);
        $template['TOURNAMENTTEAMS'] .= '<tr><td style="text-align: center;"><strong>' .$tteams['name']. '</td><td style="text-align: center;">' .$tteams['wins']. '</td><td style="text-align: center;">' .$tteams['losses']. '</td></tr>';
    }else{
        $template['TOURNAMENTTEAMS'] .= '<tr><td style="text-align: center;"><strong>No eligible teams.</td><td style="text-align: center;"></td><td></td></tr>';
    }`

Answer 1

您需要循环遍历结果，现在如果您得到 1 或 10 个结果，则只打印第一项。

if (mysql_num_rows($tteams) > 0) {
    $results = mysql_fetch_assoc($tteams);
    foreach($results as $row) {
        $template['TROURNAMENTTEAMS'] .= ... ;
    }
} else {
    $template['TROURNAMENTTEAMS'] .= ... ;
}