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javascript - JsGrid 将嵌套对象加载到表中

转载 作者:行者123 更新时间:2023-11-29 23:17:27 26 4
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我正在 Django 中开发一个 Web 项目并使用 jsGrid。我遇到了问题,但找不到解决方案。

我有一个嵌套的 JSON 数据,它是通过组合多个数据库表记录创建的。这是我的 JSON:

{  
"count":3,
"results":[
{
"personnel":{
"name":"david",
"age":34
},
"company":"IBM"
},
{
"personnel":{
"name":"john",
"age":28
},
"company":"Google"
},
{
"personnel":{
"name":"Yuri",
"age":42
},
"company":"Microsoft"
}
]
}

这是我的 js 脚本:

function () {
$("#personnelsgrid").jsGrid({
height: "500px",
width: "100%",
filtering: !0,
editing: !0,
sorting: !0,
paging: !0,
autoload: !0,
pageSize: 15,
pageButtonCount: 5,
deleteConfirm: "Do you really want to delete the client?",
controller: {
loadData: function (filter) {
return $.ajax({
type: "GET",
url: "/get_personnels",
dataType: "json",
data: filter
});
}
},
fields: [
{name: "personnel.name", type: "text", width: 50},
{name: "personnel.age", type: "number", width: 50, filtering: false},
{name: "company", type: "text", width: 200},
]

正如所见,我的数据中有一个嵌套对象。虽然 JSON 来自服务器,但它并没有加载到 jsGrid 表中。我该怎么办?

最佳答案

在您的响应中,json 数据的格式为 response.results。所以,在你的 loadData您需要使用 $.Deferred() 传递结果 的方法像这样

loadData: function(filter) {
var deferred = $.Deferred();
$.ajax({
type: "GET",
url: "/get_personnels",
dataType: "json",
data: filter,
success: function(response) {
deferred.resolve(response.results);
}
});
return deferred.promise();
}

演示

$("#jsGrid").jsGrid({
width: "100%",
height: "auto",
filtering: !0,
editing: !0,
sorting: !0,
paging: !0,

//for loadData method Need to set auto load true
autoload: true,
pageSize: 15,
pageButtonCount: 5,
deleteConfirm: "Do you really want to delete the client?",

noDataContent: "Directory is empty",

controller: {
loadData: function(filter) {
var deferred = $.Deferred();
$.ajax({
type: "get",
url: "//api.stackexchange.com/2.2/questions?order=desc&sort=activity&tagged=jsgrid&site=stackoverflow",
dataType: "json",
success: function(response) {
deferred.resolve(response.items);
}
});
return deferred.promise();
}
},

fields: [{
name: "owner.display_name",
title: 'Name',
type: "text",
width: 50
}, {
name: "title",
title: 'Title',
type: "text",
width: 200
}]
});
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<link rel="stylesheet" href="//cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.css" />

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid-theme.min.css" />

<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.js"></script>

<div id="jsGrid"></div>

关于javascript - JsGrid 将嵌套对象加载到表中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52242787/

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