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java - 登录参数不使用 Volley 通过 REST 发布

转载 作者:行者123 更新时间:2023-11-29 23:16:17 25 4
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我正在尝试让我的演示登录 Android 应用程序通过 REST 在我的服务器上使用 login.php 应用程序登录,该应用程序查询服务器上的本地 MySQL 数据库。

当我从 Insomnia 运行 REST 查询时,我指定了以下 JSON 数组:

{
"email": "cnorris@mail.com",
"password": "hello"
}

然后在响应中,我得到以下内容:

{
"login": [
{
"name": "Chuck",
"email": "cnorris@mail.com",
"id": "0"
}
],
"success": "1",
"message": "success"
}

但是在 Android 中,我得到一个空响应,这与我没有指定 JSON 数组时得到的响应相同。这是我的 LoginActivity 的样子:

package com.dafakamatt.androidregisterandlogin;

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ProgressBar;
import android.widget.TextView;
import android.widget.Toast;

import com.android.volley.AuthFailureError;
import com.android.volley.Request;
import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;
import com.android.volley.toolbox.Volley;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import java.util.HashMap;
import java.util.Map;

public class LoginActivity extends AppCompatActivity {

private EditText email, password;
private Button btn_login;
private TextView link_regist;
private ProgressBar loading;
private static String URL_LOGIN = "http://192.168.69.3/android_register_login/login.php";

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);

loading = findViewById(R.id.loading);
email = findViewById(R.id.email);
password = findViewById(R.id.password);
btn_login = findViewById(R.id.btn_login);
link_regist = findViewById(R.id.link_regist);

btn_login.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String mEmail = email.getText().toString().trim();
String mPass = password.getText().toString().trim();


if (!mEmail.isEmpty() || !mPass.isEmpty()) {
Login(mEmail, mPass);

} else {
email.setError("Please insert email");
password.setError("Please insert password");
}
}
});

link_regist.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
startActivity(new Intent(LoginActivity.this,RegisterActivity.class));
}
});

}

private void Login(final String email, final String password) {

loading.setVisibility(View.VISIBLE);
btn_login.setVisibility(View.GONE);

StringRequest stringRequest = new StringRequest(Request.Method.POST, URL_LOGIN,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject jsonObject = new JSONObject(response);
String success = jsonObject.getString("success");
JSONArray jsonArray = jsonObject.getJSONArray("login");

if (success.equals("1")) {
for (int i = 0; i < jsonArray.length(); i++) {

JSONObject object = jsonArray.getJSONObject(i);

String name = object.getString("name").trim();
String email = object.getString("email").trim();

Toast.makeText(LoginActivity.this,
"Success Login. \nYour Name: "
+ name + "\nYour Email: "
+ email, Toast.LENGTH_SHORT)
.show();
loading.setVisibility(View.GONE);

}
}

} catch (JSONException e) {
e.printStackTrace();
loading.setVisibility(View.GONE);
btn_login.setVisibility(View.VISIBLE);
Toast.makeText(LoginActivity.this, "Error " + e.toString(), Toast.LENGTH_SHORT).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
loading.setVisibility(View.GONE);
btn_login.setVisibility(View.VISIBLE);
Toast.makeText(LoginActivity.this, "Error -" + error.toString(), Toast.LENGTH_SHORT).show();
}
}) {
@Override
protected Map<String, String> getParams() {
Map<String, String> params = new HashMap<>();
params.put("email",email);
params.put("password",password);
return params;
}
};

RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);

}
}

我的猜测是被覆盖的 getParams() 方法没有完成它的工作,因为我做错了什么。

尝试登录时我的崩溃日志在这里:

W/System.err: org.json.JSONException: End of input at character 0 of 
at org.json.JSONTokener.syntaxError(JSONTokener.java:449)
W/System.err: at org.json.JSONTokener.nextValue(JSONTokener.java:97)
at org.json.JSONObject.<init>(JSONObject.java:159)
at org.json.JSONObject.<init>(JSONObject.java:176)
at com.dafakamatt.androidregisterandlogin.LoginActivity$3.onResponse(LoginActivity.java:83)
at com.dafakamatt.androidregisterandlogin.LoginActivity$3.onResponse(LoginActivity.java:79)
at com.android.volley.toolbox.StringRequest.deliverResponse(StringRequest.java:78)
at com.android.volley.toolbox.StringRequest.deliverResponse(StringRequest.java:30)
at com.android.volley.ExecutorDelivery$ResponseDeliveryRunnable.run(ExecutorDelivery.java:106)
at android.os.Handler.handleCallback(Handler.java:790)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:164)
at android.app.ActivityThread.main(ActivityThread.java:6494)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:438)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:807)

这是 AndroidManifest.xml 文件:

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.dafakamatt.androidregisterandlogin">

<uses-permission android:name="android.permission.INTERNET" />

<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:roundIcon="@mipmap/ic_launcher_round"
android:supportsRtl="true"
android:theme="@style/AppThemeLogin"
android:usesCleartextTraffic="true">
<activity android:name=".LoginActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />

<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".RegisterActivity"
android:theme="@style/AppThemeRegist">

</activity>
</application>

</manifest>

这是PHP代码:

<?php

// required headers
header("Access-Control-Allow-Origin: *");
header("Content-Type: application/json; charset=UTF-8");



if ($_SERVER['REQUEST_METHOD']=='POST') {

$json = file_get_contents('php://input');
$obj = json_decode($json);

$email = $obj->{'email'};
$password = $obj->{'password'};

require_once 'connect.php';

$sql = "SELECT * FROM users_table WHERE email='" . $email . "' ";

$response = mysqli_query($conn, $sql);

$result = array();
$result['login'] = array();

if ( mysqli_num_rows($response) === 1 ) {

$row = mysqli_fetch_assoc($response);

if ( password_verify($password, $row['password']) ) {

$index['name'] = $row['name'];
$index['email'] = $row['email'];
$index['id'] = $row['id'];

array_push($result['login'], $index);

$result['success'] = "1";
$result['message'] = "success";
echo json_encode($result);

mysqli_close($conn);

} else {

$result['success'] = "0";
$result['message'] = "error";
echo json_encode($result);

mysqli_close($conn);

}

}


}

?>

和 require_once connect.php:

<?php

$conn = mysqli_connect("localhost", "sql", "P@ssw0rd", "users");

?>

感谢任何帮助:

注意:我正在遵循本指南: https://www.youtube.com/watch?v=yS5n40h4Wlg&t=0s

最佳答案

关于这个异常,我想告诉你一件事:

org.json.JSONException: End of input at character 0 of at org.json.JSONTokener.syntaxError(JSONTokener.java:449)

这意味着您没有收到任何 JSON 响应。您需要调试代码以找出发生这种情况的原因。

我认为它有一些后端问题。

编辑:

    if ( password_verify($password, $row['password']) ) {

$index['name'] = $row['name'];
$index['email'] = $row['email'];
$index['id'] = $row['id'];

array_push($result['login'], $index);

$result['success'] = "1";
$result['message'] = "success";
return json_encode($result);

mysqli_close($conn);

} else {

$result['success'] = "0";
$result['message'] = "error";
return json_encode($result);

mysqli_close($conn);

}

关于java - 登录参数不使用 Volley 通过 REST 发布,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55310047/

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