javascript - 如何根据指定属性以外的属性数将对象附加到数组？

Question

例如，我有一个这样的对象数组:

[

{
      "waterfallData.PopulationName":"Population 1",
      "Deaths":-2333,
      "Births":8786,
      "open":0,
      "close":6453
   },
   {
      "waterfallData.PopulationName":"Population 2",
      "Deaths":-1000,
      "Births":5000,
      "open":0,
      "close":10453
   },
   {
      "waterfallData.PopulationName":"Population 3",
      "Deaths":-2000,
      "Births":500,
      "open":0,
      "close":8953
   }
]

我想像这样在每个种群之间添加两个(不一定是两个，如果有 "Extra Births" 那么三个)中间对象

[

{
      "waterfallData.PopulationName":"Population 1",
      "Death":-2333,
      "Births":8786,
      "open":0,
      "close":6453
   },
   {
      "Deaths" : -1000,
       "open"   : 6453,
       "close"  : 5453
   },
   {
     "Births" : 5000,
      "open"   : 5453,
      "close   : 10453
   }
   {
      "waterfallData.PopulationName":"Population 2",
      "Deaths":-1000,
      "Births":5000,
      "open":0,
      "close":10453
   },
   {
      "Deaths" : -2000,
      "open"    : 10453,
      "close"   : 8453
   },
   {
      "Births" : 500,
      "open"    : 8453,
      "close"   : 8953
   }
   {
      "waterfallData.PopulationName":"Population 3",
      "Deaths":-2000,
      "Births":500,
      "open":0,
      "close":8953
   }
]

正如您所看到的，我想根据 waterfallData.PopulationName 以外的属性数量添加对象, open和 close特性。然后，我想分配 open和 close每个对象的属性基于下一个 "Deaths"和 "Births"值。

例如，Population 1从 6453 开始，然后我添加两个对象，第一个对象占用下一个 "Deaths" Population 2 中的值这是 -1000 然后我分配 open属性来自以前的 close Population 1的属性(property)和 close要通过添加分配的 open 来计算的属性属性(property)"Deaths"的值(value)。第二个额外的对象也是如此，我在其中分配了 open属性为 close前一个对象的属性和 close要通过添加 open 来计算的属性与 "Births"的值(value)。

我如何实现这一目标？

Answer 1

粗糙..但有效

var newArr = [];
$x = [{
    "waterfallData.PopulationName":"Population 1",
    "Deaths":-2333,
    "Births":8786,
    "open":0,
    "close":6453
},{
    "waterfallData.PopulationName":"Population 2",
    "Deaths":-1000,
    "Births":5000,
    "open":0,
    "close":10453
},{
    "waterfallData.PopulationName":"Population 3",
    "Deaths":-2000,
    "Births":500,
    "open":0,
    "close":8953
}];
$x.forEach((p,i)=>{
    var current = $x[i]
    newArr.push(current)
    try {
        var next = $x[i+1];
        var start = current.open;
        var end = current.close;
        var states = Object.keys(current).sort().filter((k)=>{return (['waterfallData.PopulationName','open','close'].indexOf(k) < 0)})
        for (var i=0;i<states.length;i++){
            var state = states[i]
            var tempObj = {}
            tempObj[states[i]] = next[states[i]]
            tempObj['open'] = end;
            end += next[states[i]];
            tempObj['close'] = end;
            newArr.push(tempObj)
        }
    } catch (e) {
        return false;
    }
})

代码将查找除 waterfallData.Popu..、open、close 之外的所有属性，并将它们视为状态。如果你有10个属性，除了上面的3个，还有7个状态。然后从下一个元素开始计算这些状态的开盘价和收盘价，并插入新的数组newArr。