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javascript - D3.js Chord Diagram - 使和弦接触拉开的弧线

转载 作者：行者123 更新时间：2023-11-29 23:14:05 26 4
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这里是 D3 和 Javascript 新手。我正在制作一张和弦图，其中一条弧线从中心拉开。我已经设法将圆弧移动到我想要的位置，但我想知道如何使和弦组再次接触圆弧而不弄乱其他和弦组的位置？

这是一张图片来解释我想要的结果。

我目前正在使用 if 语句来选择圆弧 C 停留的 Angular 并平移其位置。

.attr("transform", function(d) {
            if (d.startAngle > Math.PI*1/2 && d.startAngle < Math.PI*5/6) {
                            return "transform", "translate(" + pullOutSize + "," + pullOutSize + ")"}
        ;})

我也可以使用翻译来翻译和弦的位置。 

.attr("transform", "translate(" + 50 + "," + 50 + ")")
.attr("d", path);

但是，当我对其应用相同的 if 语句时，翻译停止工作。好像if语句不满足条件。我想知道将什么语句放入 if 语句以帮助我选择要移动的和弦部分是正确的。

.attr("transform", function(d) {
            if (d.startAngle > Math.PI*1/2 && d.startAngle < Math.PI*5/6) {
                            return "transform", "translate(" + pullOutSize + "," + pullOutSize + ")"}
        ;})

谢谢!

最佳答案

根据文档，您可以在创建和弦/色带时将半径作为参数传递。

ribbon 的文档

// from documentation
   var ribbon = d3.ribbon();
     ribbon({
            source: {startAngle: 0.7524114, endAngle: 1.1212972, radius: 240},
            target: {startAngle: 1.8617078, endAngle: 1.9842927, radius: 240}
     }); 

<!DOCTYPE html>
<meta charset="utf-8">
<style>

body {
  font: 20px sans-serif;
}

.group-tick line {
  stroke: #000;
}

.ribbons {
  fill-opacity: 0.67;
}

</style>
<svg width="800" height="800">
<defs>
      <linearGradient id="Gradient1">
        <stop class="stop1" offset="0%"/>
        <stop class="stop2" offset="50%"/>
        <stop class="stop3" offset="100%"/>
      </linearGradient>
      <linearGradient id="Gradient2" x1="0" x2="0" y1="0" y2="1">
        <stop offset="0%" stop-color="red"/>
        <stop offset="50%" stop-color="black" stop-opacity="0"/>
        <stop offset="100%" stop-color="blue"/>
      </linearGradient>
  </defs>
</svg>
<script src="https://d3js.org/d3.v5.min.js"></script>
<script>

var matrixData={
  "Occupants":
  [0, 10,10,10,10,0,0,0,10,10,10,10,10],
  "Flooring":
  [70,0,0,0,0,0,30,0,0,0,0,0,0],
  "Millwork":
  [40, 0,0,0,0,0,60,0,0,0,0,0],
  "Ceilings": 
  [60, 0,0,0,0,0,40,0,0,0,0,0,0],
  "Wet Applied Products":
  [60, 0,0,0,0,0,40,0,0,0,0,0,0],
  "Curtain Wall":
  [0, 0,0,0,0,0,100,0,0,0,0,0,0],
  "Environment":
  [0, 10,10,10,10,0,10,0,10,10,10,0,10],
  "Roofing":
  [0, 0,0,0,0,0,80,0,0,0,0,0],
  "Insulation":
  [50, 0,0,0,0,0,50,0,0,0,0,0,0],
  "MEPFP":
  [40, 0,0,0,0,0,60,0,0,0,0,0,0],
  "Structure": 
  [50, 0,0,0,0,0,50,0,0,0,0,0,0],
  "Furniture":
  [90, 0,0,0,0,0,10,0,0,0,0,0,0]
}


matrix= Object.values(matrixData);
matrixKeys = Object.keys(matrixData);
  
var svg = d3.select("svg"),
    width = +svg.attr("width"),
    height = +svg.attr("height"),
    outerRadius = Math.min(width, height) * 0.5 - 150,
    innerRadius = outerRadius - 30;

	
	
var formatValue = d3.formatPrefix(",.0", 1e3);

var chord = d3.chord()
    .padAngle(0.024)
    .sortSubgroups(d3.descending);

var arc = d3.arc()
    .innerRadius(innerRadius)
    .outerRadius(outerRadius);

var ribbon = d3.ribbon();

var color = d3.scaleOrdinal()
    .domain(d3.range(4))
    .range(["#6FCDE3", 
            "#D7DAE5", 
            "#D7DAE5", 
            "#D7DAE5", 
            "#D7DAE5", 
            "#D7DAE5", 
            "#E5E52B",
            "#D7DAE5",
            "#D7DAE5", 
            "#D7DAE5", 
            "#D7DAE5", 
            "#D7DAE5"
           ]);

var g = svg.append("g")
    .attr("transform", "translate(" + width / 2 + "," + height / 2 + ") rotate(75)")
    .datum(chord(matrix));

var group = g.append("g")
    .attr("class", "groups")
  .selectAll("g")
  .data(function(chords) { return chords.groups; })
  .enter().append("g");

group.append("path")
    .style("fill", function(d) { return color(d.index); })
    .style("stroke", function(d) { return d3.rgb(color(d.index)).darker(); })
    .attr("d", function(d,i) { 
		var radius = 0;
		if(d.index%2 != 0) radius = 50;
		return arc.innerRadius(innerRadius + radius)
    .outerRadius(outerRadius + radius)(d);}).on("mouseover", function(d,i) {
		fade(.1,d);
	})
    .on("mouseout", function(d,i) {
		fade(1,d);
	});

var groupTick = group.selectAll(".group-tick")
  .data(function(d) { return groupTicks(d, 1e3); })
  .enter().append("g")
    .attr("class", "group-tick")
    .attr("transform", function(d) { 
	  var radius = 0;
	  if(d.index%2 != 0) radius = 50;
      return "rotate(" + (d.angle * 180 / Math.PI - 75) + 
        ") translate(" + (outerRadius + radius) + ",2)"; 
    });

groupTick.append("line")
    .attr("x2", 6);

groupTick
  .filter(function(d) { return d.value % 5e3 === 0; })
  .append("text")
    .attr("x", 8)
    .attr("dy", ".35em")
    .attr("transform", function(d) { return d.angle > Math.PI/2 && d.angle < Math.PI*3/2 ? "rotate(180) translate(-16)" : null; })
    .style("text-anchor", function(d) { return d.angle > Math.PI/2 && d.angle < Math.PI*3/2? "end" : null; })
    .text(function(d) { 
  return matrixKeys[d.index]; 
});

g.append("g")
    .attr("class", "ribbons")
  .selectAll("path")
  .data(function(chords) { 
	return chords; })
  .enter().append("path")
    .attr("d", function(d) {
		if(d.source.index%2 == 0) d.source.radius = innerRadius;
		else d.source.radius = innerRadius + 50;
		if(d.target.index%2 == 0) d.target.radius = innerRadius;
		else d.target.radius = innerRadius + 50;
		return ribbon(d);
	})
	.attr("class", function(d,i) { return matrixKeys[d.index]})
    .style("fill", function(d) { return color(d.target.index); })
    .style("stroke", function(d) { return d3.rgb(color(d.target.index)).darker(); });

		
	
// Returns an array of tick angles and values for a given group and step.
function groupTicks(d, step) {
  var k = (d.endAngle - d.startAngle) / d.value;
  return d3.range(0, d.value, step).map(function(value) {
    return {
      index:d.index,
      value: value, 
      angle: value * k + d.startAngle
    };
  });
}

function fade(opacity, d2) {
			var hightLight = g.selectAll(".ribbons path").filter(function(d) { 
				return d.source.index != d2.index && d.target.index != d2.index;
			});
			hightLight.transition()
                    .style("opacity", opacity);
        }

</script>

关于javascript - D3.js Chord Diagram - 使和弦接触拉开的弧线，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/53247071/

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