java - Android 设置具有唯一 ID 的闹钟

Question

在我的应用程序中，我使用了多个警报管理器，它们都工作正常。现在我的应用中还需要两件事:

• 为每个 alarmManager 设置一个 ID，这样我就可以在我的广播接收器中识别这个警报

• 以后使用这个id取消闹钟

我的闹钟设置代码

    Calendar cal1 = Calendar.getInstance();
    cal1.set(Calendar.HOUR_OF_DAY, h1);
    cal1.set(Calendar.MINUTE, m1+30);
    cal1.set(Calendar.SECOND, 00);

    Intent intent = new Intent(context, YourBroadCastReceiver.class);


    // Add Some unique ID here for e.g "SFSF43535"
    PendingIntent openAlarm = PendingIntent.getBroadcast(context, 0, intent, 0);
     // Add Some unique ID here for e.g "SFSf87sfs"
    PendingIntent CloseAlarm = PendingIntent.getBroadcast(context, 0, intent, 0);

    AlarmManager alarmManager = (AlarmManager) context.getSystemService(ALARM_SERVICE);

    alarmManager.setRepeating(AlarmManager.RTC_WAKEUP,
                      cal1.getTimeInMillis(), DateUtils.DAY_IN_MILLIS, openAlarm);

   alarmManager.setRepeating(AlarmManager.RTC_WAKEUP,
                      cal1.getTimeInMillis(), DateUtils.DAY_IN_MILLIS, CloseAlarm);

YourBroadCastReceiver(这里我需要唯一 ID)

  @Override
    public void onReceive(Context context, Intent intent) {
       // Get Unique id here to find some data related to that alram 
    }

Answer 1

您可以向您的 Intent 添加额外的内容，它将被传递:

Intent intent = new Intent(context, YourBroadCastReceiver.class);
intent.putExtra("id", "somerandomID");

然后将多余的部分放回接收器中:

public void onReceive(Context context, Intent intent) {
      String id = intent.getStringExtra("id");