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变量中匹配字符串内的 Javascript 循环

转载 作者:行者123 更新时间:2023-11-29 23:08:07 24 4
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我有一个可能很容易解决的问题,但我完全没有想到。非常感谢您的帮助。

我有一个文件,我搜索一个字符串然后在字符串中找到匹配项,将这些匹配项放入变量中以备后用。当字符串中有多个匹配项时,我的问题就出现了。我不知道如何在变量(找到的字符串)中循环。现在它只取代了第一次出现。我知道我需要一个循环,我只是不知道如何在变量中执行它。

谢谢你的帮助,最大

测试数据:

<warning>
<dmCode assyCode="00" disassyCode="01" disassyCodeVariant="AAA" infoCode="00W" infoCodeVariant="A" itemLocationCode="A" modelIdentCode="GAASIB0" subSubSystemCode="0" subSystemCode="0" systemCode="00" systemDiffCode="00"/>
<dmCode assyCode="00" disassyCode="02" disassyCodeVariant="AAA" infoCode="00W" infoCodeVariant="A" itemLocationCode="A" modelIdentCode="GAASIB0" subSubSystemCode="0" subSystemCode="0" systemCode="00" systemDiffCode="00"/>
<dmCode assyCode="00" disassyCode="03" disassyCodeVariant="AAA" infoCode="00W" infoCodeVariant="A" itemLocationCode="A" modelIdentCode="GAASIB0" subSubSystemCode="0" subSystemCode="0" systemCode="00" systemDiffCode="00"/>
</warning>

代码:

DMCString = warninglinebreaks.match(/<dmCode.+?>/i);
if (DMCString != null) {
DMC = DMCString[0];

match = DMC.match(/modelIdentCode="(.*?)"/im);
if (match !== null) {
var modelIdentCode = match[1];
} else {
var modelIdentCode = "";
}

match = DMC.match(/systemDiffCode="(.*?)"/im);
if (match !== null) {
var systemDiffCode = match[1];
} else {
var systemDiffCode = "";
}

var Regex = /systemCode="(.*?)"/;
var match = Regex.exec(DMC);
if (match != null) {
systemCode = match[1];

} else {
systemCode = "";
}

match = DMC.match(/\ssubSystemCode="(.*?)"/im);
if (match !== null) {
var subSystemCode = match[1];
} else {
var subSystemCode = "";
}

match = DMC.match(/subSubSystemCode="(.*?)"/im);
if (match !== null) {
var subSubSystemCode = match[1];
} else {
var subSubSystemCode = "";
}

match = DMC.match(/assyCode="(.*?)"/im);
if (match !== null) {
var assyCode = match[1];
} else {
var assyCode = "";
}

match = DMC.match(/disassyCode="(.*?)"/im);
if (match !== null) {
var disassyCode = match[1];
} else {
var disassyCode = "";
}

match = DMC.match(/disassyCodeVariant="(.*?)"/im);
if (match !== null) {
var disassyCodeVariant = match[1];
} else {
var disassyCodeVariant = "";
}

match = DMC.match(/infoCode="(.*?)"/im);
if (match !== null) {
var infoCode = match[1];
} else {
var infoCode = "";
}
match = DMC.match(/infoCodeVariant="(.*?)"/im);
if (match !== null) {
var infoCodeVariant = match[1];
} else {
var infoCodeVariant = "";
}

match = DMC.match(/itemLocationCode="(.*?)"/im);
if (match !== null) {
var itemLocationCode = match[1];
} else {
var itemLocationCode = "";
}

var sFileName = "DMC-" + modelIdentCode +"-"+ systemDiffCode +"-"+ systemCode + "-" + subSystemCode + subSubSystemCode + "-" + assyCode +"-"+ disassyCode + disassyCodeVariant +"-" + infoCode +infoCodeVariant +"-" +itemLocationCode;
}
DMCClean = Wlinebreaks.replace(DMCString, sFileName);

最佳答案

代替

DMCString = warninglinebreaks.match(/<dmCode.+?>/i);
if (DMCString != null) {
DMC = DMCString[0];

即总是只使用第一个匹配项,你应该做一个 for 循环,例如:

DMCString = warninglinebreaks.match(/<dmCode.+?>/ig);
if (DMCString != null) {
for (var i = 0; i < DMCString.length; i++) {
DMC = DMCString[i];

...

}
}

通过这种方式,您可以循环遍历匹配行 (DMCString) 的数组。还要注意为正则表达式添加的 g 标志,以匹配所有行,而不仅仅是第一行,正如@PierreC 所建议的那样。评论。

let warninglinebreaks = `
<warning>
<dmCode assyCode="00" disassyCode="01" disassyCodeVariant="AAA" infoCode="00W" infoCodeVariant="A" itemLocationCode="A" modelIdentCode="GAASIB0" subSubSystemCode="0" subSystemCode="0" systemCode="00" systemDiffCode="00"/>
<dmCode assyCode="00" disassyCode="02" disassyCodeVariant="AAA" infoCode="00W" infoCodeVariant="A" itemLocationCode="A" modelIdentCode="GAASIB0" subSubSystemCode="0" subSystemCode="0" systemCode="00" systemDiffCode="00"/>
<dmCode assyCode="00" disassyCode="03" disassyCodeVariant="AAA" infoCode="00W" infoCodeVariant="A" itemLocationCode="A" modelIdentCode="GAASIB0" subSubSystemCode="0" subSystemCode="0" systemCode="00" systemDiffCode="00"/>
</warning>
`;

DMCString = warninglinebreaks.match(/<dmCode.+?>/ig);
if (DMCString != null) {
for (var i = 0; i < DMCString.length; i++) {
DMC = DMCString[i];

console.log('DMC:', DMC);

}
}

关于变量中匹配字符串内的 Javascript 循环,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54407283/

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