php - 简单的php搜索代码不返回和结果

Question

我正在尝试让一个简单的 php 搜索脚本工作。它当前从 html 捕获数据并将其存储在 $input 中。问题是我一直从下面的脚本中得不到任何结果。但根本没有错误消息。我知道数据库中有完全匹配的数据，但当没有数据时，我不断从下面的代码中收到消息。我的 SQL 有问题吗？

<?php 
//declaring variable 
$input = $_POST['find']; 
//If they did not enter a search term we give them an error 
if ($input == "") { 
echo "You forgot to enter a search term"; 
exit; 
} 
//open connection 
$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );


//the sql statement 

$results = $dbh->prepare("select 
wp_users.ID,
wp_users.display_name,
stories.SID,
stories.story_name,
stories.category,
stories.genre
FROM stories
LEFT JOIN wp_users ON stories.ID=wp_users.ID
WHERE stories.story_name = '$input' OR stories.genre = '$input'");

$results->execute();
$row = $results->fetchAll(PDO::FETCH_ASSOC);

//giving names to the fields 
$storyname = $row['story_name']; 
$category = $row['category']; 
$genre = $row['genre']; 

//put the results on the screen 
echo "<b>$storyname</b>"; 
echo "$categoy"; 
echo "$genre<br>"; 

//This counts the number or results – and if there wasn’t any it gives a  
little message explaining that 
$anymatches=$row; 
if ($anymatches == 0) 
{ 
echo "<h3>Results</h3>"; 
echo "<p>Sorry, your search: &quot;" . $input . "&quot; returned zero  
results</p>"; 
}

?> 

Answer 1

$results = $dbh->prepare("select 
wp_users.ID,
wp_users.display_name,
news.SID,
news.story_name,
news.genre
FROM stories
LEFT JOIN wp_users ON news.ID=wp_users.ID
WHERE news.story_name = $input OR news.genre = $input");

基本上，在编写这些查询时，您需要将字符串括在引号中。现在，您的查询将包含

news.story_name=五只猫失踪

你需要它

news.story_name='五只猫失踪'

将其括在引号中 news.story_name='$input' 等等。