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mysql - 从电力读数mysql计算使用的千瓦时

转载 作者:行者123 更新时间:2023-11-29 22:46:43 25 4
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consumer_id reading_date  previous           present         KWH used

10 January 0 30 30
10 February 30 60 30
10 March 60 70 10
12 January 0 30 30
12 February 30 30 15

消费表

CREATE TABLE IF NOT EXISTS `consumption` (
`consumption_id` int(20) NOT NULL,
`reading_date` date NOT NULL,
`readings` int(20) NOT NULL,
`kwh_used` int(20) NOT NULL,
`meter_reader_id` int(20) NOT NULL,
`consumer_id` int(10) NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=35 DEFAULT CHARSET=latin1;

INSERT INTO `consumption` (`consumption_id`, `reading_date`, `readings`, `kwh_used`, `meter_reader_id`, `consumer_id`) VALUES
(14, '2013-07-30', 14386, 0, 1, 10),
(20, '2013-08-03', 14390, 0, 1, 10),
(29, '2013-07-30', 144, 0, 1, 12),
(31, '2013-07-31', 144, 0, 1, 12),
(34, '2013-08-03', 144, 0, 1, 12);

请检查下面我的查询,了解如何获得与上面发布的第一个表相同的输出。

SET @curRank1 = 0;
SET @curRank2 = 0;
SELECT
D1.reading_date
,D1.consumer_id
,D1.readings AS previous
,D2.readings AS present
,(D2.readings - D1.readings) AS kwh_used
FROM
(
SELECT M1.*, @curRank1 := @curRank1 + 1 AS rank
FROM consumption M1
LEFT JOIN consumption M2
ON Date(M1.reading_date) = Date(M2.reading_date)
AND M1.reading_date > M2.reading_date
WHERE M2.reading_date IS NULL
) D2
LEFT JOIN
(
SELECT M1.*, @curRank2 := @curRank2 + 1 AS rank
FROM consumption M1
LEFT JOIN consumption M2
ON Date(M1.reading_date) = Date(M2.reading_date)
) D1
ON D2.rank = (D1.rank + 1)
WHERE D1.reading_date IS NOT NULL

该查询的输出是这样的

reading_date    consumer_id     previous    present    kwh_used     
2013-07-30 10 14386 14390 4
2013-07-30 12 144 144 0
2013-08-03 10 14390 144 -14246
2013-08-03 12 144 144 0

正如您所看到的,查询返回了一系列读数,这是不好的,因为读数具有不同的consumer_id。请让我知道我在这里缺少什么。

谢谢。

最佳答案

您应该添加:

and M1.consumer_id = m2.consumer_id

每个子查询,以及它们之间的连接类似。

我认为有更简单的方法来获得你想要的东西(相关子查询或使用变量)。但如果您想修复查询,请将 consumer_id 放入连接条件中。

关于mysql - 从电力读数mysql计算使用的千瓦时,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29064812/

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